Mark as brainiest
1) place the compass needle on the external point r.2) make the compass width greater than the distance from r to the given line.
3) draw an arc cutting the given line at two points.
4) mark and label the points of intersection p and q.
5) without changing the compass width, move the compass needle to q and draw another arc below the line crossing the previous arc.
6) move the compass needle to p and make an arc below the line.
7) mark and label the point of intersection s.
8) draw a line from the external point r to the point where the arcs intersect, s.
9) line rs is perpendicular to line pq and passes through the external point r.
Answer:
f(x) = 6x² - 24x + 21
Step-by-step explanation:
The equation of a quadratic function in vertex form is
f(x) = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k ) = (2, - 3 ) , then
f(x) = a(x - 2)² - 3
To find a substitute (1, 3 ) into the equation
3 = 1(1 - 2)² - 3
3 = a(- 1)² - 3
3 = a - 3 ( add 3 to both sides )
6 = a
f(x) = 6(x - 2)² - 3 ← in vertex form
= 6(x² - 4x + 4) - 3
= 6x² - 24x + 24 - 3
f(x) = 6x² - 24x + 21 ← in standard form
Answer:The Absolute Value of a number tells us how far the number is from zero, on a Number Line. 2 is 2 units away from zero. Hence |2|=2.hope it helps
Step-by-step explanation:
Answer: option d. C (0,3), D (0,5).
Justification:
1) The x - coordinates of the vertices A and B are shown in the diagrama, They are both - 4, so the new vertices C and D must be in a line parallel to y = - 4.
2) The y-coordinates of the vertices A and B are also shown in the diagrama. They are equal to 3 and 5 respectively.
3) We can see that the new points C and D must be over a parallel line to y = - 4 and that their distance to the points A and B has to be the same distance of the point R and S to U and T.
That distance is 4, so the line may be y = - 7 or y = 0.
4) If the line is y = 7 the points C and D would have coordinates (-7,3) and (-7,5), but this points are not among the options.
5) If the line is y = 0 the points C and D would have coordinates (0, 3) and (0,5), which is precisely the points of the option d. That is the answer.
