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grigory [225]
2 years ago
13

1. Solve the equation using square roots. x² +10=9

Mathematics
1 answer:
quester [9]2 years ago
8 0

Answer:

<h2><u><em>x=±√−1 (NO REAL SOLUTION)</em></u></h2>

Step-by-step explanation:

x² + 1 = 0

1× x²+1=0

x=±√(−1×1)

x=±√−1 (NO REAL SOLUTION)

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Use the formula for continuous compounding to compute the balance in the account after 1,5, and 20 years. Also, find the APY for
densk [106]

Answer:

After 1 year: $7,256.59

After 5 years: $8,380.52

After 20 years: $14,381.03

APY = 3.66%

Step-by-step explanation:

If you deposit $7000 with an interest of 3.6%, after 1 year using continuous compounding, you will have

7000e^{0.036}=7,256.59

After 5 years you will have

7000e^{5(0.036)}=8,380.52

After 20 years

7000e^{20(0.036)}=14,381.03

To find the APY for the account, we have to compute the interest earned in one year.

We can do it by cross multiplying or by finding a number x such that

7000(1+\frac{x}{100})=7,256.59

Operating on this equation we obtain

x = 0.0366 or 3.66%

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If the number of observations for each sample is 150 units, what is the 3-sigma upper control limit of the process
bixtya [17]

Complete Question

Complete Question is attached below

Answer:

UCL= 0.25

Step-by-step explanation:

From the question we are told that:

Sample sizen=150

Sample Variants s=7

Sigma control limits  Z = 3

Therefore

Total number of observations is Given as

T_o=n*s

T_o=150 *7

T_0=1050

Generally

Summation of defectivee

\sum np=23+34+15+30+25+22+18

\sum np= 167

Generally the equation for P-bar is mathematically given by

P-bar=\frac{\sum np}{T_o}

P-bar=\frac{167}{1050}

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Therefore

Sp=\sqrt{\frac{P-bar(1-P-bar)]}{ n}}

Sp=\sqrt{\frac{[0.159(1-0.159)]}{150}}

Sp=0.03

Generally the equation for 3-sigma upper control limit of the process is mathematically given by

UCL = P-bar + Z*Sp

UCL= 0.16 + 3*0.03

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What is (2x-6)(3x-5) equaled to?
Luba_88 [7]

Answer:

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Step-by-step explanation:

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