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Karolina [17]
3 years ago
8

What passes through the points (-4,3) and (-4,-2)

Mathematics
1 answer:
stich3 [128]3 years ago
7 0
The equation of the line through those two points is . . . . . . . . . . X = -4 . / / / The line has no y-intercept and undefined slope. It's the vertical line that crosses the x-axis at -4 and goes up and down forever.
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Choose the equivalent system of linear equations that will produce the same solution as the one given below:
skelet666 [1.2K]
D is the answer as the both have solution x=-2 y=3
14x=-28       12(-2)-3y=-33
x=-2              -3y=-9
                       y=3
from the given equation
4x-y=11 eq 1
2x+3y=5 eq 2
x=y-11/4 from equation 1
subsitute this value of x in equation 2
2(y-11/4)+3y=5
y-11+6y=10
7y-11=10
y=3
subsitude this value of y in equation (x=y-11/4)
so x= -2 
thus same solution so ANSWER IS D
3 0
3 years ago
ABCD is a rhombus. If m<1=122, then what is the measure of <2 and <3
Svetach [21]
M < 2 will be 180 - 122 =  58 degrees

< 3 is opposite < 1 so it will be = 122 degrees
4 0
4 years ago
PLEASE TRY TO HELP !
Rufina [12.5K]

Answer:

the photo is a little blurry I cannot answer the question unfortunately sorry

5 0
3 years ago
7. The points P(2, -3), Q(3, -2) and R(8, z) are
Hatshy [7]

Answer:

z = 3

Step-by-step explanation:

Since the points are collinear then the slopes between the points are equal.

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = P (2, - 3) and (x₂, y₂ ) = Q (3, - 2)

m = \frac{-2+3}{3-2} = 1

Repeat with

(x₁, y₁ ) = Q (3, - 2) and (x₂, y₂ ) = R (8, z )

m = \frac{z+2}{8-3} = \frac{z+2}{5} , then

\frac{z+2}{5} = 1 ( multiply both sides by 5 )

z + 2 = 5 ( subtract 2 from both sides )

z = 3

4 0
3 years ago
Number 8 please thanks!
WINSTONCH [101]

4b(b+2)=16+4b^2\\4b^2+8b=16+4b^2\\8b = 16 + 4b^2-4b^2\\8b = 16\\b = 2

Hope that helps!

4 0
3 years ago
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