Ask question

Ask question

All categories

3 years ago

14

How are reciprocals used in division with rational numbers?

2 answers:

Neko [114]3 years ago

8 0

Answer:

When dividing rational numbers, multiply by the "right" reciprocal. In this case, the "right" reciprocal means to take the reciprocal of the fraction on the right-hand side of the division operator.

dsp733 years ago

5 0

Answer: multiply by the right reciprocal.

NOTE//the reciprocal of an rational number is the Rational Number Obtained after interchanging the Numerator and Denominator is called Reciprocal of a Rational Number.

Step-by-step explanation:

You might be interested in

Help please im so lost with this (30 points)

zepelin [54]

Answer:

10 cm the ansswer could me 5cm half

Step-by-step explanation:

8 0

3 years ago

NEED HELP NOW 100 POINTS WILL MARK BRAINLIEST ANSWER!!!! 2 photos below PLZ ANSWER BOTH CORRECTLY

slega [8]

The first answer is C.
The second answer is A.

7 0

3 years ago

Read 2 more answers

£100 will buy lunches for 80 school children for 5 days

Veronika [31]

80 children x 5 days = 400 total lunches.

£100 / 400 lunches = £0.25 per lunch

The cost for one lunch for one student is £0.25

8 0

3 years ago

Maria and farida has 250 beads altogether. After Maria used 18 beads to make a bracket and farida gave away 2/5 of her beads, th

Elenna [48]

Answer:

Maria had 105 beads at first.

Step-by-step explanation:

Let number of beads Maria have be x.

Let number of beads Farida have be y.

Given:

Maria and Farida has 250 beads altogether.

Hence equation is represented as;

$x+y =250 \ \ \ \ equation \ 1$

Also Given:

Maria used 18 beads to make a bracket.

hence bead left with maria = $x-18$

farida gave away 2/5 of her beads.

Hence beads left with Farida = $y - \frac{2}{5}y= \frac{5y}{5}-\frac{2y}{5}=\frac{5y-2y}{5}=\frac{3y}{5}$

Also they have the same number of beads left.

bead left with maria = beads left with Farida

$x-18= \frac{3y}{5}\\5(x-18)=3y\\5x-90=3y\\5x-3y =90 \ \ \ \ equation \ 2$

Now Multiplying equation 1 with 3 we get;

$3(x+y)=3\times250 = 3x+3y = 750 \ \ \ \ equation \ 3$

Now adding equation 2 by equation 3 we get;

$(5x-3y)+(3x+3y) = 750+90\\5x-3y+3x+3y = 840\\8x=840\\x=\frac{840}{8}=105$

we know the value of x = 105

hence substituting value of x in equation 1 we get;

$105+y=250\\y=250-105 =145$

Maria had 105 beads and Farida had 145 beads at first.

Final Answer: Maria had 105 beads at first.

7 0

3 years ago

Frank wants to know how many people live in each household in his town. He conducts a random survey of 10 people and asks how ma

bagirrra123 [75]

The mean absolute deviation for this is 1.6

3 0

3 years ago