Question

If an emitter current is changed by 4 mA, the collector current changes by 3.5 mA. The value of beta will be :​

Answer 1

Given -:

change in emitter current, ∆l(E) = 4 mA

change in collector current,∆I(C) = 3.5 mA

To find -:

value of B

Solution :-

∆I(E) = ∆I(C) + ∆l(B), here ∆l(B) is the change in base current.

4 = 3.5 + ∆l(B)

∆I(B) = 0.5 mA

Now, B = ∆l (C) ÷ ∆l (B)

B = 3.5 ÷ 0.5

B = 7.0

so, the value of A = 7.0