Given the objective function C=3x−2y and constraints x≥0, y≥0, 2x+y≤10, 3x+2y≤18, identify the corner point at which the maximum
value of C occurs.
1 answer:
Answer:
Step-by-step explanation:
Find the maximum value of
C = 3x -2y Objective function
subject to the following constraints.
Constraints
x ≥ 0
y ≥ 0
2x + y ≤ 10 vertex 1 : when x=0 then y=10 (0,10)
3x + 2y ≤ 18 vertex 2 : y=0, then x=6 ( 6,0)
two equations together to determine vertex 3 :
3x+2y = 18
2x+y = 10
x=2, y= 6
The feasible region determined by the constraints is
shown. The three vertices are (0, 10), and (6, 0), (0,9)
and (2,6)
First evaluate C = 3x -2 y at each of the vertices.
At (0, 10): C = 3(0) - 2(10) = -17
At (6, 0): C = 3(6) - 2(0) = 18
At ( 2,6) : C = 3(2) -2(6) = -6
At (0,9) : C = 3(0)-2(9)= -18
the maximum value occur on 18 when x=9 and y=0
You might be interested in
Given the function:
Let's find the amplitude and period of the function.
Apply the general cosine function:
Where A is the amplitude.
Comparing both functions, we have:
A = 1
b = 4
Hence, we have:
Amplitude, A = 1
To find the period, we have:
Therefore, the period is = π/2
The graph of the function is shown below:
The parent function of the given function is:
Let's describe the transformation..
Apply the transformation rules for function.
We have:
The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.
ANSWER:
Amplitude = 1
Period = π/2
Transformation = horizontal compression.
