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joja [24]
3 years ago
10

Given the objective function C=3x−2y and constraints x≥0, y≥0, 2x+y≤10, 3x+2y≤18, identify the corner point at which the maximum

value of C occurs.

Mathematics
1 answer:
ira [324]3 years ago
7 0

Answer:

Step-by-step explanation:

Find  the maximum value of

C = 3x -2y  Objective function

subject to the following constraints.

Constraints

x ≥ 0

y ≥ 0                

2x + y ≤ 10  vertex 1 : when x=0 then y=10  (0,10)

3x + 2y ≤ 18 vertex 2 : y=0, then x=6          ( 6,0)

two equations together to determine vertex 3 :

3x+2y = 18

2x+y = 10

x=2, y= 6

The feasible region determined by the constraints is

shown. The three vertices are (0, 10),  and (6, 0), (0,9)

and (2,6)

First evaluate C = 3x -2 y at each of the vertices.

At (0, 10): C = 3(0) - 2(10) = -17

At (6, 0): C = 3(6) - 2(0) = 18

At ( 2,6) : C = 3(2) -2(6) = -6

At (0,9) : C = 3(0)-2(9)= -18

the maximum value occur on 18 when x=9 and y=0

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Answer:

k=88

Step-by-step explanation:

as 8*11=88

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Explanation
8 0
3 years ago
Simplify each expression.
kati45 [8]

1:13x-14

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3: 20x-18

4:5x+15

5:14n+36

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8 0
2 years ago
100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!
Volgvan

Using weighed averages, it is found that:

  1. The final grade is 91.
  2. The final grade is 66.8.
  3. The higher grade would be 79.55, with the second grading scheme.
  4. On average, she sold $48,280 per day.
  5. On average, she makes $12.5 per hour.

---------------------------------------

To find the weighed average, we multiply each value by it's weight.

---------------------------------------

Question 1:

  • Grade of 91, with a weight of 67%.
  • Grade of 91, with a weight of 33%.

Thus:

F = 91\times0.67 + 91\times0.33 = 91

The final grade is 91.

---------------------------------------

Question 2:

  • Grade of 83, with a weight of 40%(highest grade).
  • Grade of 60, with a weight of 30%.
  • Grade of 52, with a weight of 30%.

Thus:

F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8

The final grade is 66.8.

---------------------------------------

Question 3:

With teacher 1:

  • 75 with a weight of 25%.
  • 80 with a weight of 10%.
  • 85 with a weight of 40%.
  • 62 with a grade of 25%.

Thus:

F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25

---------------------------------------

With teacher 2:

  • 75 with a weight of 15%.
  • 80 with a weight of 10%.
  • 85 with a weight of 60%.
  • 62 with a weight of 15%.

Thus:

F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55

The higher grade would be 79.55, with the second grading scheme.

---------------------------------------

Question 4:

  • Average of $36,432, with a weight of \frac{3}{3+10} = \frac{3}{13}
  • Average of $51,834, with a weight of \frac{10}{13}

Thus:

A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280

On average, she sold $48,280 per day.

---------------------------------------

Question 5:

  • Average of $14.84, with a weight of \frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}
  • Average of $10.76, with a weight of \frac{4}{7}

Thus:

A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353

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Under a dilation with a scale factor of 4/5 a 10-inch segment becomes a ___ -inch segment.
julsineya [31]

Answer:

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Step-by-step explanation:

dilation actor = 4/5

Scale dilation is used to change the dimensions of the line segment or anuy measurement in length.

So, 10 inch segment = \frac{4}{5}\times 10=8 inch

thus, the 10 inch segment is equal to 8 inch on the scale.

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