How to determine the width/thickness of a coin using a screw gauge?

1 answer:

5 0

We can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.

<h3>How we can calculate the thickness using screw gauge?</h3>

We can determine the width/thickness of a coin by using a screw gauge because screw gauge is an instrument that measures thickness of an object that are very thin. First we can placed the coin in between the teeth of the gauge and then move the gauge until the coin can be held tightly. After that note the reading on the scale.

So we can conclude that we can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.

Learn more about thickness here: brainly.com/question/4937019

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square root A 1400 kg car is coasting on a horizontal road with a speed of 18 m/s . After passing over an unpaved, sandy stretch

Lina20 [59]

Answer:

The net force on the car is 2560 N.

Explanation:

According to work energy theorem, the amount of work done is equal to the change of kinetic energy by an object. If ' $W$ ' be the work done on an object to change its kinetic energy from an initial value ' $K_{i}$ ' to the final value ' $K_{f}$ ', then mathematically,

$W = K_{f} - K_{i} = \dfrac{1}{2}~m~(v_{f}^{2} - v_{i}^{2})........................................(I)$

where ' $m$ ' is the mass of the object and ' $v_{i}$ ' and ' $v_{f}$ ' be the initial and final velocity of the object respectively. If ' $F_{net}$ ' be the net force applied on the car, as per given problem, and ' $s$ ' is the displacement occurs then we can write,

$W = F_{net}~.~s.......................................................(II)$

Given, $m = 1400~Kg,~v_{i} = 18~m~s^{-1}~v_{f} = 14~m~s^{-1}~and~s = 35~m$ .

Equating equations (I) and (II),

$&& - F_{net} \times 35~m = \dfrac{1}{2} \times 1400~Kg~\times(14^{2} - 18^{2})~m^{2}~s^{-2}\\&or,& F_{net} = \dfrac{\dfrac{1}{2} \times 1400~Kg~\times(14^{2} - 18^{2})}{35}~N\\&or,& F_{net} = 2560~N$