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3 years ago

The position of a ball as a function of time is given by

Physics

1 answer:

Andre45 [30]3 years ago

6 0

Answer:

x = -6.5 meters

Explanation:

The position of a ball as a function of time t is given by :

$x=3\ m+(-5\ m/s)t$ ..................(1)

Where t is time in seconds

We need to find the position of the ball at 1.9 s. It can be simply calculated putting t = 1.9 s in equation (1) as :

$x=3+(-5)(1.9)$

x = -6.5 meters

So, the position of the ball at 1.9 seconds is -6.5 meters. Hence, this is the required solution.

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Why dont you fall through walls when you lean against them? provide a scientific explanation to explain your answer.

kondaur [170]

Answer:

That's why if you lean against the wall, you don't just fall through it. The wall pushes back on you as hard as you push on it, and you and the wall stay in place. If you throw something, you put more force behind it than just leaning on it, so it pushes back with more force.

Explanation:

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6 0

3 years ago

a golfer hits a golf ball with a velocity of 36.0 meters/second at an angle of 28.0. if the hang time of the golf ball is 33.4 s

Kobotan [32]

Solving this using the time, we know that range = horizontal velocity x time of flight

since there are no horizontal forces acting on the ball, there are no horizontal accelerations and the initial horizontal velocity of 36 cos 28 will be constant throughout. If we use the correct time of flight given the launch parameters, we have

range = 36 cos 28 x 3.44 s = 109.3 m

6 0

2 years ago

During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of

olasank [31]

Answer:

3.416 m/s

Explanation:

Given that:

mass of cannonball $m_A$ = 72.0 kg

mass of performer $m_B$ = 65.0 kg

The horizontal component of the ball initially $\mu_{xA}$ = 6.50 m/s

the final velocity of the combined system v = ????

By applying the linear momentum of conservation:

$m_A \mu_{xA}+m_B \mu_{xB} = (m_A+m_B) v$

$72.0 \ kg \times 6.50 \ m/s+65.0 \ kg \times 0 = (72.0 \ kg+65.0 \ kg) v$

$468 kg m/s + 0 = (137 kg)v$

$v = \dfrac{468\ kg m/s }{137 \ kg}$

v = 3.416 m/s

8 0

2 years ago

Explain why a roller coaster’s second hill cannot be taller than the first hill.

max2010maxim [7]

There will not be enough momentum from the first hill to cross another hill if he same or larger size because of the way potential energy and kinetic energy works it will not be able go as high as it could go on he fist hill.

4 0

2 years ago

Read 2 more answers

In a physics laboratory experiment, a coil with 200 turns enclosing an area of 13.1 cm2 is rotated during the time interval 3.10

sergij07 [2.7K]

Answer:

A) $\Phi=83.84\times 10^{-9}$

B) $\Phi=0 Wb$

C) $emf=5.4090\times 10^{-4}V$

Explanation:

Given that:

no. of turns i the coil, $n=200$

area of the coil, $a=13.1 \times 10^{-4}\,m^2$

time interval of rotation, $t=3.1\times 10^{-2}\,s$

intensity of magnetic field, $B=6.4\times 10^{-5}\,T$

(A)

Initially the coil area is perpendicular to the magnetic field.

So, magnetic flux is given as:

$\Phi=B.a\,cos \theta$ ..................................(1)

$\theta$ is the angle between the area vector and the magnetic field lines. Area vector is always perpendicular to the area given. In this case area vector is parallel to the magnetic field.