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3 years ago

The position of a ball as a function of time is given by

Physics

1 answer:

Andre45 [30]3 years ago

6 0

Answer:

x = -6.5 meters

Explanation:

The position of a ball as a function of time t is given by :

$x=3\ m+(-5\ m/s)t$ ..................(1)

Where t is time in seconds

We need to find the position of the ball at 1.9 s. It can be simply calculated putting t = 1.9 s in equation (1) as :

$x=3+(-5)(1.9)$

x = -6.5 meters

So, the position of the ball at 1.9 seconds is -6.5 meters. Hence, this is the required solution.

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pogonyaev

Cells undergo cell division ( creates more cells to replace dead cells )

8 0

3 years ago

In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 8.13 km mark at a

SOVA2 [1]

Answer: $0.084 m/s^2$

Explanation:

Given

Total time=27 min 43.6 s=1663.6 s

total distance=10 km

Initial distance $d_1=8.13 km$

time taken=25 min =1500 s

initial speed $v_1=\frac{8.13\times 1000}{25\times 60}=5.6 m/s$

after 8.13 km mark steve started to accelerate

speed after 60 s

$v_2=v_1+at$

$v_2=5.6+a\times 60$

distance traveled in 60 sec

$d_2=v_1\times 60+\frac{a60^2}{2}$

$d_2=336+1800 a$

time taken in last part of journey

$t_3=1663.6-1560=103.6 s$

distance traveled in this time

$d_3=v_2\times t_3$

$d_3=\left ( 5.6+a\times 60\right )103.6$

and total distance $=d_1+d_2+d_3$

$10000=8.13\times 1000+336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$1870=336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$a=0.084 m/s^2$

5 0

3 years ago

A wave can be best defined as <br><br> P.S pls help

Sidana [21]

Answer:

It should be A. Disturbance that travels through a medium or space, transmitting energy from one point to another.

I hope this helped you :)

4 0

3 years ago

Solve for the BMI weight 58kg Height 1.61

vaieri [72.5K]

Answer:

Explanation:

BMI= weight/(height × height) ; weight in kilogram and height in metter

= 58kg / (1.61m × 1.61m )

= (58/ 2.5921) kg/ $m^{2}$

= 22.375 kg/ $m^{2}$

≈ 22.4 kg/ $m^{2}$

7 0

3 years ago

Suppose a clay model of a koala bear has a mass of 0.200 kg and slides on ice at a speed of 0.750 m/s. It runs into another clay

kaheart [24]

Answer:

0.278 m/s

Explanation:

We can answer the problem by using the law of conservation of momentum. In fact, the total momentum before the collision must be equal to the total momentum after the collision.

So we can write:

$mu=(m+M)v$

where

m = 0.200 kg is the mass of the koala bear

u = 0.750 m/s is the initial velocity of the koala bear

M = 0.350 kg is the mass of the other clay model

v is their final combined velocity

Solving the equation for v, we get

$v=\frac{mu}{m+M}=\frac{(0.200)(0.750)}{0.200+0.350}=0.278 m/s$

8 0

4 years ago