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Gemiola [76]
3 years ago
13

Which particles are heavy and which are light

Physics
2 answers:
VashaNatasha [74]3 years ago
3 0

Answer:

Protons and neutrons are heavy, Electrons are extremely light

Explanation:

Protons and neutrons are heavier than electrons and reside in the nucleus at the center of the atom. Electrons are extremely lightweight and exist in a cloud orbiting the nucleus.

aleksklad [387]3 years ago
3 0
Protons- heavy
Electrons- light
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The dwarf planet Ceres contains over 50% of the mass of the main asteroid belt.
PolarNik [594]

False

Explanation:

Called an asteroid for many years, Ceres is so much bigger and so different from its rocky neighbors that scientists classified it as a dwarf planet in 2006. Even though Ceres comprises 25 percent of the asteroid belt's total mass, tiny Pluto is still 14 times more massive.

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2 years ago
How much heat in joules is required to melt an ice cube with a mass of 18.6 g at 0 °C? The Lf for water is 333 J/g.
EastWind [94]

Answer:

The heat energy required, Q = 6193.8 J

Explanation:

Given,

The mass of ice cube, m = 18.6 g

The heat of fusion of ice, ΔHₓ = 333 J/g

The heat energy of a substance is equal to the product of the mass and heat of fusion of that substance. It is given by the equation,

                               <em> Q = m · ΔHₓ     joules</em>

Substituting the given values in the above equation

                                Q = 18.6 g x 333 J/g

                                    = 6193.8 J

Hence, the heat required to melt the ice cube is, Q = 6193.8 J

5 0
3 years ago
[1] The assembly starts from rest and reaches an angular speed of 150 rev/min under the action of a 20-N force T applied to the
ExtremeBDS [4]

Answer:

t = 5.89 s

Explanation:

To calculate the time, we need the radius of the pulley and the radius of the sphere which was not given in the question.

Let us assume that the radius of the pulley (r_p) = 0.4 m

Let the radius of the sphere (r) = 0.5 m

w = angular speed = 150 rev/min = (150 × 2π / 60) rad/s = 15.708 rad/s

Tension (T) = 20 N

mass (m) = 3 kg each

\int\limits^0_t {Tr_p} \, dt=H_2-H_1\\( Tr_p)t=4rm(rw)\\( Tr_p)t=4r^2mw

t = \frac{4r^2mw}{Tr_P}

Substituting values:

t = \frac{4r^2mw}{Tr_P}= \frac{4*(0.5)^2*3*15.708}{20*0.4}=5.89s

7 0
3 years ago
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zepelin [54]
Answer is: 1973.17N aprox.
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3 years ago
Parker wound a wire around a large iron nail. He then created an electromagnet by connecting the ends of the wire to different b
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The correct option is C.
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3 years ago
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