Explanation:
A logarithm in one base is a constant multiple of a logarithm in any other base. Any "order of ..." specification does not include the applicable constant multiplier or the smaller order terms that may be required for an exact computation.
The concept of "order of" is similar to the concept of the degree of a polynomial. Knowing the degree of a polynomial tells you something about the "end behavior" as the function argument gets large. The specifics of the scale factor and lower-degree terms become largely irrelevant.
Answer:
Option A, 2^(1/6)
Step-by-step explanation:
<u> is same as 2^(1/2)</u>
<u />![\sqrt[3]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D)
<u> is same as 2^(1/3)</u>
<u />
2^(1/6)
Answer: Option A, 2^(1/6)
Answer:
6.5 hours
Step-by-step explanation:
52 divided by 6 = 6.5
Answer:
1 1/3
Step-by-step explanation:
Randy studied for the same amount of time so it would be the same answer im not sure if I'm correct but hope this helps
Answer:
H = 60(3/4)^x
Step-by-step explanation:
After each bounce, the height it reach is 3/4 the previous one.
Let the height of nth bounce be denoted as h_n and the first bounce is h_1.
We are given that h_1 = 60 cm. Following the rule in the problem, we get:
h_2 = (3/4)h_1 = (3/4)60
h_3 = (3/4)h_2 = (3/4)*(3/4)60 = 60(3/4)^2
h_4 = (3/4)h_3 = (3/4)*60(3/4)^2= 60(3/4)^3
We see that h_n = 60(3/4)^n is the formula for the height for the nth bounce. Therefore, H = 60(3/4)^x is the answer.
I hope this helps! :)
