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Llana [10]
2 years ago
7

You're ordering a sandwich at the local deli, below is a tree diagram of the possible orders. What is the probability that your

sandwich has turkey AND swiss cheese?

Mathematics
1 answer:
dusya [7]2 years ago
4 0

Answer:

Step-by-step explanation:

1. So there is two bread options but let's ignore that due every option being the same for both bread options.

2. So if you look there are three meat options meaning there is a one in three chance logical chance someone picks turkey (note when I say logical I mean that doesn't mean that this will be true in real life) and there is a one in two logical chance someone picks Swiss cheese.

3. So with a one in three chance logical meat option and a one two chance cheese option and.

4. Now knowing this it is simple math at this point as simple as \frac{1}{3} x \frac{1}{2}

5. 1 x 1 = 1 and 3 x 2 = 6

6. leading to \frac{1}{6}

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Ivenika [448]
1.50 / 4 = .50  ,   $.50  for 4 eggs
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3 years ago
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Compute the line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the l
SIZIF [17.4K]

Answer:

\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}

Step-by-step explanation:

The line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the line segment from (1, 1, 1) to (2, 2, 2) followed by the line segment from (2, 2, 2) to (−9, 6, 5) equals the sum of the line integral of f along each path separately.

Let  

C_1,C_2  

be the two paths.

Recall that if we parametrize a path C as (r_1(t),r_2(t),r_3(t)) with the parameter t varying on some interval [a,b], then the line integral with respect to arc length of a function f is

\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{a}^{b}f(r_1,r_2,r_3)\sqrt{(r'_1)^2+(r'_2)^2+(r'_3)^2}dt

Given any two points P, Q we can parametrize the line segment from P to Q as

r(t) = tQ + (1-t)P with 0≤ t≤ 1

The parametrization of the line segment from (1,1,1) to (2,2,2) is

r(t) = t(2,2,2) + (1-t)(1,1,1) = (1+t, 1+t, 1+t)

r'(t) = (1,1,1)

and  

\displaystyle\int_{C_1}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(1+t,1+t,1+t)\sqrt{3}dt=\\\\=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)(1+t)^2dt=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)^3dt=\displaystyle\frac{15\sqrt{3}}{4}

The parametrization of the line segment from (2,2,2) to  

(-9,6,5) is

r(t) = t(-9,6,5) + (1-t)(2,2,2) = (2-11t, 2+4t, 2+3t)  

r'(t) = (-11,4,3)

and  

\displaystyle\int_{C_2}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(2-11t,2+4t,2+3t)\sqrt{146}dt=\\\\=\sqrt{146}\displaystyle\int_{0}^{1}(2-11t)(2+4t)^2dt=-90\sqrt{146}

Hence

\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{C_1}f(x,y,z)ds+\displaystyle\int_{C_2}f(x,y,z)ds=\\\\=\boxed{\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}}

8 0
3 years ago
Point Q' is the image of Q(-4, 7) under a translation by 4 units to the right and 2 units down.
Reil [10]

Answer:

Q' ( 0,5)

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Q(-4, 7)

To shift to the right, add the amount to x

x+4

To shift down, subtract from y

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Q' ( 0,5)

3 0
3 years ago
Jennifer had $24 to spend on five pens. After buying them she had $14. How much did each pen cost?
Strike441 [17]

Answer:

Each pen costed $5.

Step-by-step explanation:

Simple, the coefficient (5) is the cost for one of the pens & the x is the amount of pens bought.

Hope this helped & please give me the brainliest if it did!

4 0
2 years ago
Help algebra 2 please
34kurt

Answer:

option 4

Step-by-step explanation:

(f*g)(x) =(x² + x+ 1)*(x² - x -1)

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           = x⁴  - x³ + x³  - x² - x² + x² - x - x - 1

       = x⁴ - x² - 2x - 1

4 0
2 years ago
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