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2 years ago

1. A partially completed chart shows the hierarchy of a set of polygons.

Mathematics

1 answer:

lana [24]2 years ago

5 0

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Please find the attached file for the complete solution.

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Expand each expression In 4y5/x2

nordsb [41]

Answer:

$\ln 4 -2 \ln x +5 \ln y$

Step-by-step explanation:

$\ln \dfrac{4y^5}{x^2}\\\\=\ln(4y^5) - \ln(x^2)~~~~~~~~~~~;\left[ \log_b\left( \dfrac mn \right) = \log_b m - \llog_b n \right]\\\\=\ln 4 + \ln y^5 - 2\ln x~~~~~~~~~~~~;[\log_b m^n = n \log_b m ~\text{and}~\log_b(mn) = \log_b m + \log_b n ]\\\\=\ln 4 + 5 \ln y -2 \ln x\\\\=\ln 4 -2 \ln x +5 \ln y$

3 0

1 year ago

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PLEASE HELP ASAP For each expression below, select the letter that corresponds to the equivalent expression from the given list.

LenaWriter [7]

BAnswer:

B-D-A

Step-by-step explanation:

4 0

3 years ago

the number of girls and boys in math class totals 27. how many girls are there if the of girls is 3 more than twice the number b

leonid [27]

Answer: 15 girls

Step-by-step explanation:

27 - 3 = 24

24/2 = 12

12 boys

12 + 3 = 15

15 girls

15+ 12 = 27

7 0

2 years ago

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What is the best next step in the construction of the perpendicular bisector of

Musya8 [376]

C, not sure but C. It makes sense to me & I got it right when I did it

4 0

3 years ago

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Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro

Elanso [62]

Answer:

<em>Choose the first alternative</em>

$\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}$

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions $(N_s)$ and the total number of possible choices $(N_t)$ , i.e.

$\displaystyle P=\frac{N_s}{N_t}$

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

$_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}$

The total number of possible choices is

$_{2}^{20}\textrm{C} \text{ ways to do it}$

The probability is then

$\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}$

Choose the first alternative

7 0

2 years ago

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