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uysha [10]
3 years ago
15

A meat market sold five 7/5 pounds of meatballs on Monday six 1/2 pounds of meat balls on Tuesday and 4 pounds of meatballs on W

ednesday how many pounds of meatballs did they selling all three days
Mathematics
1 answer:
Whitepunk [10]3 years ago
8 0

Answer:

Add all of them together. So your answer is

61/10 or 6 and

Step-by-step:

7/5 =1 and 2/5 or 14/10

1/2= 5/10

4/1 or 4= 40/10

14/10 + 5/10 + 40/10 = 61/10

Simplified: 6 and 1/10

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Slope is 5 and y intersept is 5over6

Step-by-step explanation:

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Verify the identity. sin() tan() = cos() use a reciprocal identity to rewrite the expression in terms of sine and cosine, and th
Andreas93 [3]

The identity Sin(α)/Tan(α) = Cos(α) is valid

Trigonometry is study of triangles. All trigonometric ratios are defined using the sides of the right triangle, such as an adjacent side, opposite side, and hypotenuse side. Three major of them are as follows :-

Sine Function:

sin(θ) = Opposite / Hypotenuse

Cosine Function:

cos(θ) = Adjacent / Hypotenuse

Tangent Function:

tan(θ) = Opposite / Adjacent

Lets prove this identity by proceeding with the LHS

= Sin(α)/Tan(α)

= Sin(α)/ (Sin(α)/Cos(α)) (Tan(α) = Sin(α)/Cos(α))

= Sin(α)xCos(α) / Sin(α)

= Cos(α)

Hence verified

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2 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

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$p_2=\frac{86}{155}=0.554839

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The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

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soldi70 [24.7K]

Answer:

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It is in the form of n:1 where n is 0.5.

brainliest if im correct? :)

Step-by-step explanation:

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