15·x²=15·x so
x²=x
x·x=x with x≠0 than x must be 1
x=1
V = lwh
2x³ + 17x² + 46x + 40 = l(x + 4)(x + 2)
2x³ + 12x² + 16x + 5x² + 30x + 40 = l(x + 4)(x + 2)
2x(x²) + 2x(6x) + 2x(8) + 5(x²) + 5(6x) + 5(8) = l(x + 4)(x + 2)
2x(x² + 6x + 8) + 5(x² + 6x + 8) = l(x + 4)(x + 2)
(2x + 5)(x² + 6x + 8) = l(x + 2)(x + 4)
(2x + 5)(x² + 2x + 4x + 8) = l(x + 4)(x + 2)
(2x + 5)(x(x) + x(2) + 4(x) + 4(2)) = l(x + 4)(x + 2)
(2x + 5)(x(x + 2) + 4(x + 2)) = l(x + 4)(x + 2)
(2x + 5)(x + 4)(x + 2) = l(x + 4)(x + 2)
(x + 4)(x + 2) (x + 4)(x + 2)
2x + 5 = l
Answer:
1 / 663
Step-by-step explanation:
First, let's find the total number of ways you can pick 2 cards from the deck. This is 52 * 51 = 2652 because there are 52 cards available for your first pick, and after you pick one, you'll have 51 left for your second pick.
There are 4 5's (one for every suite) and only 1 Queen of Hearts in a deck of cards. Therefore, the total number of successful outcomes will be 4 * 1 = 4.
The probability of picking a 5 and then a Queen of Hearts is 4 / 2652 =
1 / 663. Hope this helps!
Answer:
The question is x^2 = 20, right? then
second option is the answer
