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Vesna [10]
1 year ago
12

Quadrilateral WXYZ has vertices W(2, 10), X(10, 10), (10,2), and Z(2, 2). Determine if quadrilateral WXYZ is a rhombus.

Mathematics
1 answer:
Oliga [24]1 year ago
7 0

Answer:

B. Yes, quadrilateral WXYZ is rhombus because the sides are perpendicular.

Step-by-step explanation:

1) according to the given coordinates the equations of the sides are:

YZ: y=2; WZ: x=2; WX: y=10; XY: x=10. It means

2) YZ⊥WZ; YZ⊥XY; WX⊥XY; WX⊥WZ. To the additional, WX=WZ=YZ=XY, then

3) the given quadrilateral is sqare (rhombus with angles m∠=90°).

4) finally, the correct answer is

B. Yes, quadrilateral WXYZ is rhombus because the sides are perpendicular.

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