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3 years ago

Hiiiiiiiiiiiiii there

Mathematics

1 answer:

Ivenika [448]3 years ago

5 0

Answer:

D. 18.18

Step-by-step explanation:

Based on the information given we would set up the ratio

$\frac{27.5}{25} = \frac{20}{x}$ We then cross multiply to get 20x25=27.5x

multiply

500=27.5x

divide to solve for x

x=18.18

width = 18.18

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Help, please I need a mathswatch answer this is from the mathswatch website

torisob [31]

Answer:

158.76

Step-by-step explanation:

11.7*15.6=182.52

182.52/2=91.26

Area of BCD=91.26

7.5*18=135

135/2=67.5

Area of BAD=67.5

Altogether:

91.26+67.5=158.76

4 0

3 years ago

Kelly leaves her home and cycles 4y miles south then cycles (3y + 9) miles east

atroni [7]

4y(3y + 9)
12y + 36
36 ÷ 12=x=3

7 0

3 years ago

Tate is saving his money to buy a go-cart. The go-cart he wants costs $240. His mom agreed to chip in $60. What % of the total c

enot [183]

The answer is 25%.

60/240=x/100
60*100=6000
6000/240=25

60/240=25/100

7 0

3 years ago

Using the slope formula, find the slope of the line through the given points.<br> (1,6) and (3,4)

svlad2 [7]

To find slope you do y2-y1 over x2-x1. So 4-6 is -2. And 3-1 is 2. So -2/2 is -1. The slope is -1.

7 0

3 years ago

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

The estimate is $- 0.0265\le K \le 0.0465$

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

3 0

3 years ago