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Naddik [55]
3 years ago
5

PLASS HELPPP WILL GIVE BRAINLISTTT DUE RN

Mathematics
1 answer:
scoray [572]3 years ago
4 0

Answer:

The area of the rectangle is 0.0875  sq ft.

Step-by-step explanation:

Given that,

The length of the rectangle, L = 0.35 feet

The breadth of the rectangle, B = 1/4 feet

We need to find the area of the rectangle. The formula for the area of a rectangle is given by :

A = LB

Put all the values,

A=\dfrac{1}{4}\times 0.35\\\\A=0.0875\ ft^2

So, the area of the rectangle is 0.0875  sq feet.

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Vlad [161]

The  values of the given numbers when it is rounded up to the nearest 10 thousands are:

  • 990000
  • 150000

<h3>What is rounding up in mathematics?</h3>

Rounding up can be described as the process that is been used in the mathematics which is been used in the estimation of a particular number in a context.

It should be noted that in rounding the  a number up, it is required to look at the next digit at the right hand of the given figures in a case whereby the digit is less than 5,the digit can be rounded down, but in the case whereby the digit is more that 5 then it can be rounded up .

From the given values, we are given the 990,201 and 159,994  and if this were to rounded up to the nearest 10 thousand then we will start from the right hand sides and round down the values less than 5 and round up the values that is more that 5. and their values will be 990000

and 150000.

Read more about rounding up at:

brainly.com/question/28324571

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8 0
1 year ago
Prove that u(n) is a group under the operation of multiplication modulo n.
katrin2010 [14]

Answer:

The answer is the proof so it is long.

The question doesn't define u(n), but it's not hard to guess.


Group G with operation ∘

For all a and b and c in G:

1) identity: e ∈ G, e∘a = a∘e = a,

2) inverse: a' ∈ G, a∘a' = a'∘a = e,

3) closed: a∘b ∈ G,

4) associative: (a∘b)∘c = a∘(b∘c),

5) (optional) commutative: a∘b = b∘a.


Define group u(n) for n prime is the set of integers 0 < i < n with operation multiplication modulo n.


If n isn't prime, we exclude from the group all integers which share factors with n.


Identity: e = 1. Clearly 1∘a = a∘1 = a. (a is already < n).


Closed: u(n) is closed for n prime. We must show that for all a, b ∈ u(n), the integer product ab is not divisible by n, so that ab ≢ 0 (mod n). Since n is prime, ab ≠ n. Since a < n, b < n, no factors of ab can equal prime n. (If n isn't prime, we already excluded from u(n) all integers sharing factors with n).


Inverse: for all a ∈ u(n), there is a' ∈ u(n) with a∘a' = 1. To find a', we apply Euclid's algorithm and write 1 as a linear combination of n and a. The coefficient of a is a' < n.


Associative and Commutative:

(a∘b)∘c = a∘(b∘c) because (ab)c = a(bc)

a∘b = b∘a because ab = ba.


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