Answer:
Point of intersections are (0, -7) and (5, -2).
Step-by-step explanation:
From the graph attached,
A straight line is intersecting the circle at the two points (0, 7) and (5, -2).
Now solve algebraically,
Equation of the line → y = x - 7 -------(1)
Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)
By substituting the value of y from equation (1) to equation (2)
(x - 5)² + (x - 7 + 7)² = 25
(x - 5)² + x² = 25
x² - 10x + 25 + x² = 25
2x² - 10x = 0
x² - 5x = 0
x(x - 5) = 0
x = 0, 5
From equation (1),
y = 0 - 7 = -7
y = 5 - 7 = -2
Therefore, point of intersections are (0, -7) and (5, -2).
4.5 is the answer
Divide 49 from both sides
220.5 / 49 = 4.5
I) 80% x 5640 = Rs. 4512
ii) 4512 divide by 50 = Rs. 90.24
Answer:
f(n) = -n^2 -3n +5
Step-by-step explanation:
Suppose the formula is ...
f(n) = an^2 +bn +c
Then we have ...
f(1) = 1 = a(1^2) +b(1) +c
f(2) = -5 = a(2^2) +b(2) +c
f(3) = -13 = a(3^2) +b(3) +c
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Here's a way to solve these equations.
Subtract the first equation from the second:
-6 = 3a +b . . . . . 4th equation
Subtract the second equation from the third:
-8 = 5a +b . . . . . 5th equation
Subtract the fourth equation from the fifth:
-2 = 2a
a = -1
Then substituting into the 4th equation to find b, we have ...
-6 = 3(-1) +b
-3 = b
and ...
1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation
5 = c
The formula is ...
f(n) = -n^2 -3n +5
