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3 years ago

6

please help me i suck at math and really need help i know u probly dont care lol but i need help below

1 answer:

sergiy2304 [10]3 years ago

8 0

The equation of the line is C. 1X/2 -2
How you figure this out is you first say when x is zero y is what?
y= 1/2 (0) - 2
You would then see that y=-2 (0,-2)
Plot that point
Next you need to find the slope of the line.
Remember slope is rise over run.
When you 'rise' up one (from -2) and 'run' 2
you are now at the point (2,-1) which is on the line.
You can continue doing rise/run along the line to check your answer.
I hope this makes sense! Let me know if you have any questions :)

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2m = 480.6 what is the value of m

ivolga24 [154]

Step-by-step explanation:

2m=480.6

To get m you gotta divide 480.6 by 2

To make m the subject of the formula you have to make 2 cross over to the other side I. E over the equal sign

I. E 480.6/2=240.3

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3 years ago

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-7=y/-10<br> Help me, please

emmainna [20.7K]

Answer:

70

Step-by-step explanation:

Solve any pre-algebraic equation with inverse operations:

-7 = y/-10

multiply both sides by -10

-7 * -10 = y

now simplify:

remember that multiplying two negatives with result in a positive

70 = y

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3 years ago

Jose bought 6 chicken wings for $2. What was the cost of the wings in wings per dollar? Express your answer in simplest form.

pogonyaev

Answer:

0.5$each

Step-by-step explanation:

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3 years ago

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Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

Step-by-step explanation:

The given equation is

$x^3-21x=-20$

It can be written as

$x^3+0x^2-21x+20=0$

Splitting the middle terms, we get

$x^3-x^2+x^2-x-20x+20=0$

$x^2(x-1)+x(x-1)-20(x-1)=0$

$(x-1)(x^2+x-20)=0$

Splitting the middle terms, we get

$(x-1)(x^2+5x-4x-20)=0$

$(x-1)(x(x+5)-4(x+5))=0$

$(x-1)(x+5)(x-4)=0$

Using zero product property, we get

$x-1=0\Rightarrow x=1$

$x-4=0\Rightarrow x=4$

$x+5=0\Rightarrow x=-5$

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

$x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}$

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

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3 years ago

Factorise x^2-3x+10=0

Mila [183]

(x-5)(x+2)=0
roots: x=5 and x= -2
see attached photo for steps

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3 years ago

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