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3 years ago

Which expression correctly represents “three less than the product of a number and two, increased by five”?

Mathematics

2 answers:

DerKrebs [107]3 years ago

7 0

It would be 3-2x+5 hoped that helped

ira [324]3 years ago

5 0

Answer:

Let x represents the number.

Given the statement: "Three less than the product of a number and two, increased by five".

"Product" means multiply

"Product of a number and two" translated to $2x$

"Three less than the product of a number and two" translated to 2x - 3

Increased by 5 means +5

then;

the given statement becomes;

$(2x-3)+5$

Therefore, the expression that represents "three less than the product of a number and two, increased by five" is $(2x-3)+5$

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Find the value of y if given: 20y-2, 17y +3, 5x + 8, 21x

rodikova [14]

20y-2=
20y=2
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y=0.1

17y +3=
17y=-3
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3 years ago

Help anyone? please?

ValentinkaMS [17]

Answer:

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Step-by-step explanation:

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Distribute:

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I'm not sure if this is the correct answer but I hope this helps! :)

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3 years ago

A delivery truck drove 203 mi in 3.5 h. After unloading and loading new cargo, it traveled on another 243 mi for 4.5 h.

sveticcg [70]

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Read 2 more answers

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

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3 years ago