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maks197457 [2]
3 years ago
6

An oak tree is 60 feet tall and casts a 40-foot shadow. What is the approximate distance from the top of the oak tree to the top

its shadow?
Mathematics
2 answers:
Murljashka [212]3 years ago
7 0
The approximate distance from the top of the tree to the top of the shadow is 20ft
Naddik [55]3 years ago
3 0

Answer:

the top of the tree to the top of the shadow is 20ft

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write an equation in slope intercept form for the line described. perpendicular to y = -1/2x + 2/3, passes through (2,3)
Alex17521 [72]

Step-by-step explanation:

Hey there!

Follow the steps to get answer.

  • Use one point formula and find 1st equation.
  • After that you find the slope of second equation.
  • Use the condition of perpendicular lines and find the slope of first equation.
  • Put slope value of equation in equation (i) and simplify them to get equation.

The equation of a line passing through point (2,3) is;

(y-3)= m1(x-2).......(i).

Another equation is;

y =  \frac{ - 1}{2} x +  \frac{2}{3}

2nd equation..

Now, From equation (ii)

We have;

Comparing equation (ii) with y = mx+c.

We get;

Slope = -1/2.

For perpendicular lines,

m1 \times m2 =  - 1

m1 \times  \frac{ - 1}{2}  =  - 1

Therefore the slope is 2.

Put value of slope (m1) in equation (i). We get;

(y - 3) = 2(x - 2)

Simplify them to get equation.

(y - 3) = 2x - 4

y = 2x - 1

Therefore the required equation is y = 2x-1.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
Use the law of cosines to gind the value of x and y.​
ivanzaharov [21]

Answer: Answer:x = 49.8^\circ\\y = 54.6^\circStep-by-step explanation: Kindly refer to the image attached in the answer region for labeling of triangle.

Step-by-step explanation: u multiply the numbers

4 0
2 years ago
a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

=2\frac{17}{24}-\frac{3}{8}

\frac{48+17}{24}-\frac{3}{8}

=\frac{65}{24}-\frac{3}{8}

=\frac{65-9}{24}

=\frac{56}{24}

\frac{7}{3}

=2\frac{1}{3} minutes


3 0
3 years ago
Read 2 more answers
Please help me. I don’t understand this at all...
mylen [45]
Problem 1

With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2

Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)

Use examples like this and you'll get the results you see in "figure 1"

For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.

=======================================================

Problem 2

This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers. 

6 0
3 years ago
Plssss answer! Your team is renting a photo booth for the 8th grade dance, but you have to buy the photo paper and other supplie
Rama09 [41]

Answer:

$215.25

Step-by-step explanation:

4 0
3 years ago
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