Rewrite each expression using each base only once.
(-6)^12 * (-6)^3 * (-6)^2
(-6)^(12+3+2)
(-6)^(17)
Answer:
(-6)^(17)
2^2 * 2^7 * 2^0
(2)^(2+7+0)
(2)^(9)
Answer:
(2)^(9)
Simplify each expresion.
5c^4 * c^6
5*c^(4+6)
5*c^(10)
Answer:
5*c^10
(-2.4n^4)(2n^-1)
(-2.4*2)(n^4)(n^-1)
(-2.4*2)(n^(4+(-1))
(-4.8)(n^(4-1))
(-4.8)(n^(3))
Answer:
(-4.8)(n^(3))
(4c^4)(ac^3)(-3a^5c)
((4)*(-3))*(c^(4+3+1))*(a^(1+5))
(-12)*(c^(8))*(a^(6))
Answer:
(-12)*(c^8)*(a^6)
a^6b^3 * a^2b^-2
(a^(6+2))*(b^(3+(-2)))
(a^(8))*(b^(3-2))
(a^(8))*(b^(1))
(a^8)*(b)
Answer:
(a^8)*(b)
Graph the inequality by finding the boundary line, then shading the appropriate area.
They are congruent. Distance formula works.
Answer:
A. 20t² + 9t - 20
Step-by-step explanation:
(5t × 4t) + (5t × 5) - (4 × 4t) - (4 × 5)
= 20t² + (25t - 16t) - 20
= <u>20t² + 9t - 20</u> (A)
<em>Hope </em><em>this </em><em>is </em><em>h</em><em>e</em><em>l</em><em>p</em><em>ful </em><em>and </em><em>useful </em><em>:</em><em>)</em>
I was going to say that you would need to change the mixed numbers into an improper fraction but then I realized that they both have the same denominator (4), meaning that in this case if the whole number outside of the fraction is bigger than the one for the other then it’s greater than regardless.
6 is greater than 5, so
5¾<6¼
