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Svetlanka [38]
3 years ago
7

Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms.

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
5 0
C quadratic function
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The principal P is borrowed at a simple interest rate r for a period of time t. Find the​ loan's future value​ A, or the total a
Julli [10]

The​ loan's future value​ A, or the total amount due at time t is $1105.

Given, P = ​$1000​, r = 3.5​%, t = 3 months.

We need to find the loan's future value A.

<h3>What is Simple interest?</h3>

Simple interest is computed on the principal amount of a loan or the first deposit in a savings account. Simple interest does not compound, therefore an account holder will only get interest on the principal, and a borrower will never have to pay interest on previously collected interest.

We know that, Simple Interest=\frac{P\times\ T \times\ R }{100}

Now, Simple Interest=\frac{1000\times3\times3.5}{100\times12}

=\frac{10,500}{100} =105

As we know, Amount=Principal+Simple Interest

=1000+105=1105

Hence, the​ loan's future value​ A, or the total amount due at time t is $1105.

To know more about simple interests visit:

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2 years ago
Pls help w math !
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The answer is -7
4+-7=-3
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Question 4 (1 point)
Phantasy [73]

Answer:

its 43

Step-by-step explanation:

as x was 1 in the first problem

you add X (1) by 42 and get

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Graph for the quadratic formula f(x) = (x - 3) ^2 +5
aksik [14]

Please see the attached graph to see f(x) = (x - 3) ^2 +5 graphed.

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3 years ago
Circle assignment! THANKS so much its worth so much of my grade
kogti [31]

Answer:

1. B) Figure B.

2. C) Figure C.

3. D) Figure D.

4. C) Figure C.

Step-by-step explanation:

Given: Radius of Circle A= 4

           Radius of Circle B= 5

           Radius of circle C= 6

           Radius of circle D= 7

Now, finding circumference and area of all the circle.

We know, circumference of circle= 2\pi r

Area of circle= \pi r^{2}

Where, r= radius of circle and π = 3.14

First, solving for figure A

Circumference= 2\times 3.14\times 4= 25.12\ cm

Area= 3.14\times 4^{2} = 50.24\ cm^{2}

Solving for Figure B

Circumference= 2\times 3.14\times 6= 31.4\ cm

Area= 3.14\times 5^{2} = 78.5\ cm^{2}

Solving for Figure C

Circumference= 2\times 3.14\times 6= 37.68\ cm

Area= 3.14\times 6^{2} = 113.04\ cm^{2}

Solving for Figure D

Circumference= 2\times 3.14\times 7= 43.96\ cm

Area= 3.14\times 7^{2} = 153.86\ cm^{2}

∴ 1. Answer is Figure B.

   2. Answer is figure C.

   3. Answer is Figure D

   4. Answer is Figure C.

6 0
3 years ago
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