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KengaRu [80]
3 years ago
15

Anyone know what this is

Mathematics
2 answers:
ioda3 years ago
5 0

Answer:

D: No, because on x-values corresponds to two different y-values.

Step-by-step explanation:

Two of the y-values are the same with different x-values

and so is x 8 couldn't be 5 and 8 it would have to have the same y-value

RUDIKE [14]3 years ago
4 0
D No, because one x-value corresponds to two different y-values
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Solve: 8.2 = 3.4 + d d = _____
Alinara [238K]

Answer:

4.8

Step-by-step explanation:

You just subtract to solve for d so,

8.2 = 3.4 + d

-3.4   -3.4

4.8 = d

8 0
3 years ago
2. Solve - Sy + 13y<br> 45 for y.
zimovet [89]
This makes no sense
5 0
3 years ago
What must m∠QPS be for PQRS to be a parallelogram?
solmaris [256]

Answer:

18

Step-by-step explanation:

5 0
3 years ago
Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
3 years ago
Jeff was already 7 miles out of town when his sister
Nikolay [14]

The sister catches up Jeff after 2 hours

Step-by-step explanation:

We can write Jeff's position and his sister position at time t using the following expressions:

- Jeff position:

x_j(t) = 7 + 2.5 t

where:

7 is the initial position of Jeff when his sister sarts chasing him

2.5 is Jeff's velocity (in miles/hour), so its position increases by 2.5 miles for each hour

t is the time measured in hours

- Sister position:

x_s(t) = 6t

where

6 is the sister velocity (her position increases by 6 miles for every hour)

t is the time measured in hours

The sister catches up Jeff when the two positions are equal, so

x_j(t) = x_s(t)\\7+2.5t=6t

And solving for t,

7+2.5t-2.5t=6t-2.5t\\7=3.5t\\t=\frac{7}{3.5}=2 h

So, the sister catches Jeff after 2 hours.

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

5 0
3 years ago
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