Question

A coordinate plane with a line passing through points (1, 2) and (4, 4)

Answer 1

A straight line is represented by a linear equation given below.

The points are given as (1, 2) and (4, 4).

Start by calculating the slope (m)

$m=\frac{y_2-y_1}{x_2-x_1}$

So, we have

$m=\frac{4-2}{4-1} \\m=\frac{2}{3}$

What is the slope-intercept form of the line?

The equation in slope-intercept form is then calculated as:

$y=m(x-x_1)+y_1$

So, we have:

$y=\frac{2}{3}(x-1)+2\\ \\y=\frac{2}{3}(x-4)+4$

Expand

$y=\frac{2}{3}(x-1)+2\\ y=\frac{2}{3} x-\frac{2}{3}+2$

Take LCM

$y=2/3x+4/3$

Multiply through by 3

3y=2x+4

So, the possible equations are:

.$3y=2x+4\\y=\frac{2}{3}x+\frac{4}{3} \\y=\frac{2}{3}(x-1)+2\\y=\frac{2}{3}(x-4)+{4}$

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Answer 2

Answer:

B

C

E

Step-by-step explanation:

other dudes are  wrong