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Lorico [155]
3 years ago
14

How do I solve this equation?

Mathematics
1 answer:
kow [346]3 years ago
8 0

Answer:    2 * sqrt(2)        

I attached an image to show you what I mean

Step-by-step explanation:

First add 20 on both sides

5x^(2 / 3) = 10

divide both sides by 5

x^(2 / 3) = 2

Now be reminded that the power of 2/3 is the same as x^2 cube root (to the third root)

So we now cube both sides to get rid of the cube root

x^2 = 2^3

which simplifies to x^2 = 8

We now just find the square root of both sides

so x = sqrt(8)

square root of 8 is simply sqrt(4 * 2) = sqrt(4) * sqrt(2) = 2 * sqrt(2)

So x = 2 * sqrt (2)

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3 years ago
What is the value of the entry represented by c41
Elenna [48]

<u>ANSWER</u>

C_{41}=2

<u>EXPLANATION</u>

This very simple to do.

First locate the entry in A_{41} in matrix A. That is the entry in the intersection of the fourth row and first column of matrix A. This entry is  7.

Then multiply by the scalar which is 2 to get,

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Next we locate the entry in B_{41} in matrix B also. Which is 4. We multiply by the scalar of -3 to get,

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See diagram

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3 years ago
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MariettaO [177]

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Step-by-step explanation:

Given

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See attachment

Required

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Read 2 more answers
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