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2 years ago

13

Is salmon fortified or enriched?

1 answer:

Greeley [361]2 years ago

6 0

It is fortified w vitamin d

You might be interested in

what is the oxidation state of each element in coh2? c o h what is the oxidation state of each element in febr3? fe br

fgiga [73]

The oxidation state of the elements in the compounds are:

CoH₂:

Co = +2
H = -1

FeBr₃:

Fe = +3
Br = -1

<h3>What is the oxidation states of the elements in the given compounds?</h3>

The oxidation states of the elements in each of the given compounds is determined as follows:

Cobalt dihydride, CoH₂

Co = +2

H = -1

Iron (iii) bromide, FeBr₃

Fe = +3

Br = -1

In conclusion, the oxidation state of the elements are charges they have in the compound.

Learn more about oxidation state at: brainly.com/question/27239694

#SPJ1

8 0

2 years ago

1. Which of the combinations in the lab activity had indications that a chemical change occured? Defend your argument with evide

ArbitrLikvidat [17]

Answer:The green growing on the penny of copper and the rust forming on the nail of iron are chemical changes. Boiling away salt water, scraping iron filings from a mixture of sand with a magnet, and breaking a rock with a hammer, are physical changes.

Explanation:

4 0

3 years ago

Quickly Please!!!!!!

FrozenT [24]

Answer:

$n=4.1mol$

Explanation:

Hello,

In this case, we can use the ideal gas equation:

$PV=nRT$

So we know the temperature, pressure and volume, therefore we can easily compute the required moles as shown below:

$n=\frac{PV}{RT}=\frac{2.0atm*101L}{0.082\frac{atm*L}{mol*K}*600K} \\\\n=4.1mol$

Best regards.

5 0

3 years ago

Read 2 more answers

Write the balanced molecular, ionic, and net ionic equations for the reaction when a solution of lithium phosphate is mixed with

Kaylis [27]

Answer:

see explaination

Explanation:

Molecular equation;

2Li3PO4(aq) + 3CaCl2(aq) >>>> Ca3(PO4)2(s) + 6LiCl(aq)

Total ionic equation; . Includes all ions ;

6Li^+(aq) + 2PO4^-3(aq) + 3Ca^+2(aq) + 6Cl^-(aq) >>>> Ca3(PO4)2(s) + 6Li^+(aq) + 6Cl^-(aq)

Net ionic equation; remove common ions from total ionic;

2PO4^-3(aq) + 3Ca^+2(aq) >>>> Ca3(PO4)2(s)

6 0

3 years ago

A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu

OLEGan [10]

Answer: The final temperature of nickel and water is $25.2^{o}C$ .

Explanation:

The given data is as follows.

Mass of water, m = 55.0 g,

Initial temp, $(t_{i}) = 23^{o}C$ ,

Final temp, $(t_{f})$ = ?,

Specific heat of water = 4.184 $J/g^{o}C$ ,

Now, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$

Also,

mass of Ni, m = 15.0 g,

Initial temperature, $t_{i} = 100^{o}C$ ,

Final temperature, $t_{f}$ = ?

Specific heat of nickel = 0.444 $J/g^{o}C$

Hence, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

$q_{water}(gain) = -q_{alloy}(lost)$

$55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$ = -( $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$ )

$t_{f} = \frac{25.9^{o}C}{1.029}$

= $25.2^{o}C$

Thus, we can conclude that the final temperature of nickel and water is $25.2^{o}C$ .

6 0

3 years ago