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MaRussiya [10]
3 years ago
7

How many grams of O2(g) are needed to completely burn 15.6 g of C3H8(g)?

Chemistry
1 answer:
alexdok [17]3 years ago
7 0
15.6gC3H8*44.1gC3H8*32gO2=11.32
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svet-max [94.6K]
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I hope these answers will help you! If you need any explanation, ask and hopefully I can get back to you. ;)
8 0
3 years ago
what can we tell about an unknown substance based on its properties. Its science btw, i couldnt find the science subject
dsp73

Answer:

Measuring its density and comparing your result to a list of known densities, or other properties that give you useful info

Explanation:

You can use observations about substances to form a hypothesis about the substance by comparing it to others. Ex: if something is magnetic it must be made of one or more of the elements iron, cobalt, or nickel.

6 0
3 years ago
Which of the following solutions is more concentrated?<br> 0.50M KCl or 5.0% (w/v) KCl
HACTEHA [7]

.50 M KCl because 5% is the same as .05, which makes the .50M more concentrated.

6 0
3 years ago
Most elements are _____? <br><br> nonmetals <br> metalloids<br> metals
NARA [144]

Answer:Most elements on the periodic table are metals. Looking at the periodic table shows that most elements are metallic.

Explanation: Sorry if this want what you were looking for

4 0
2 years ago
When heated, lithium reacts with nitrogen to form lithium nitride: 6Li(s) + N2(g) → 2Li3N(s) What is the theoretical yield of Li
anyanavicka [17]

Answer:

The % yield of the reaction = 27.5 %

Explanation:

Step 1: Data given

Mass of Li = 12.7 grams

Mass of N2 = 34.7 grams

Actual yield of Li3N = 5.85 grams

Molar mass of  Lithium = 6.94 g/mol

Molar mass of N2 = 28 g/mol

Molar mass of LI3N = 34.83 g/mol

Step 2: The balanced equation:

6Li(s) + N2(g) → 2Li3N(s)

Step 3: Calculate moles of Lithium

Moles Li = mass Li / Molar mass Li

Moles Li = 12.7 grams / 6.94 g/mol

Moles Li = 1.83 moles

Step 4: Calculate moles of N2

Moles N2 = 34.7 g/ 28 g/mol

Moles N2 = 1.24 moles

Step 5: Limiting reactant

For 6 moles Li consumed, we need 1 mole of N2 to produce 2 moles of Li3N

Lithium is the limiting reactant. It will completely be consumed (1.83 moles).

N2 is in excess. There will be consumed 1.83 / 6 = 0.305 moles

There will remain 1.24 - 0.305 = 0.935 moles

Step 6: Calculate moles of Li3N

For 6 moles Li consumed, we need 1 mole of N2 to produce 2 moles of Li3N

For 1.83 moles Li, we'll have 1.83/3 = 0.61 moles of Li3N

Step 7: Calculate mass of Li3N

Mass Li3N =moles LI3N * Molar Mass LI3N

Mass Li3N = 0.610 moles * 34.83 g/mol

Mass Li3N = 21.2463 grams = Theoretical yield

Step 8: Calculate % yield

% yield = actual yield / theoretical yield

% yield = (5.85 / 21.2463)*100% = 27.5%

The % yield of the reaction = 27.5 %

8 0
3 years ago
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