1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?
Point Slope form y − y1 = m(x − x1)
Y1: -7 x1:1 slope :-2/3
Y-(-7)=-2/3(x-1)
Y+7=-2/3(x-1)
2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?
Y-(-6)=1/3(x-(-2))
Y+6=1/3(x+2)
3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)
SlopeM: =change in y/change in x
M= -1-5/-3-4
M= -6/-7
M=6/7
So now slope:6/7, point (4,5)
Y-y1=m(x-x1)
Equation in point slope
Y-5=6/7(x-4)
The slope is -1 because the number beside x is always the slope and the y-intercept is 1 because the number being added or subtracted from x is always the y intercept
Answer:
18
Step-by-step explanation:
f(x) = x³+4x²-8x-6
P(a) <=> P(x)
-2 | 1 4 -8 -6
|
| -2 -4 24
----------------------------
1 2 -12 18
Calculate and multiply to get
-4/(-6)+7 - 2x(-2)/-1x3+7
Next remove parentheses and calculate,
You'll get -4/-6+7 - 2x(-2)/4
Then calculate and reduce,
-4/1 - -2/2
Reduce and divide to get -4-(-1)
Remove parentheses, -4+1
And calculate to get your final answer
= -3
The x axis is the one going this way : ——— the y is the opposite going up so you just have to number it and add the dots
