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Makovka662 [10]
1 year ago
5

Students were asked to prove the identity (sec x)(csc x) = cot x + tan x. ​

Mathematics
1 answer:
pogonyaev1 year ago
8 0

Let's prove that (sec x)(csc x) is equal to cot x + tan x

\Longrightarrow  \sf (sec(x) )(csc(x))

\Longrightarrow  \sf \dfrac{1}{\cos \left(x\right)\sin \left(x\right)}

\Longrightarrow  \sf \dfrac{\cos ^2\left(x\right)+\sin ^2\left(x\right)}{\cos \left(x\right)\sin \left(x\right)}

\Longrightarrow  \sf \dfrac{\cos ^2\left(x\right)}{\cos \left(x\right)\sin \left(x\right)} + \dfrac{\sin ^2\left(x\right)}{\cos \left(x\right)\sin \left(x\right)}

\Longrightarrow  \sf \dfrac{\cos\left(x\right)}{\sin \left(x\right)} + \dfrac{\sin \left(x\right)}{\cos \left(x\right)}

\Longrightarrow  \sf cot(x)  + tan(x)

Hence student A did correctly prove the identity properly.

Also Looking at student B's work, he verified the identity properly.

So, Both are correct in their own way.

<h3>Part B</h3>

Identities used:

\rightarrow \sf sin^2 (x) + cos^2 (x) = 1       (appeared in step 3)

\sf \rightarrow \dfrac{cos(x) }{sin(x) }  = cot(x)               (appeared in step 6)

\rightarrow \sf \dfrac{sin(x )}{cos(x) }  = tan(x)               (appeared in step 6)

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rewrite 1st eq. as y = 20/x

subsituute that into 2nd eq.

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