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2 years ago

8

A circle with radius 9 has a sector with a central angle of 120°. What is the area of the sector. Provide step by step explanati

on please

1 answer:

inn [45]2 years ago

6 0

Okay, so you find the area of the full circle, 81pi and then 120 is 1/3 of the circle so you divide 81pi by 3 and get 27pi.

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Terra writes the following proof for the theorem: If the diagonals of a quadrilateral bisect each other, the quadrilateral is a

Brrunno [24]

Answer:

you are correct and pls dont delete this anwser if i get it wrong side B

Step-by-step explanation:

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2 years ago

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47/100+3/10+47/100=/100

ira [324]

Answer:

The total is 97/100

Step-by-step explanation:

47/100+3/100=50/100 (aka 1/2)

50/100+47/100=97/100

5 0

1 year ago

3x/3=? I WILL MARK U BRAINLIST!!!!!

insens350 [35]

Answer:

3 x 3 =9

Step-by-step explanation:

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4 0

2 years ago

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Factor completely 20x^3y + 30x^2y^2.

weqwewe [10]

Answer:

10x^2 y(2x + 3y)

Step-by-step explanation:

20x^3 y + 30x^2 y^2.

Factor 10x^2y out of 20x^3y.

10x^2 y (2x) + 30x^2 y^2

Factor 10x^2y out of 30x^2y^2.

10x^2 y (2x) + 10x^2 y (3y)

Factor 10x^2y out of 10x^2 y (2x) + 10x^2 y (3y).

10x^2 y(2x + 3y)

you factor out 10x^2y from both side which you will then get 10x^2 y (2x) + 10x^2 y (3y) than you factor out 10x^2y again and get 10x^2 y(2x + 3y) your third option

6 0

2 years ago

The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of

romanna [79]

Answer: a) $\dfrac{3}{874}$

b) $\dfrac{30}{3059}$

c) $\dfrac{3575}{12236}$

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : $11+13=24$

Total number of ways to structure a jury of six people from a group of 24 people :-

$^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596$

a) Number of ways of selecting a jury of all students :-

$^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{462}{134596}=\dfrac{3}{874}$

b) Number of ways of selecting a jury of all faculty :-

$^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{1716}{134596}=\dfrac{30}{3059}$

c) Number of ways of selecting a jury of two students and four faculty :-

$^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325$

Then , the probability of selecting a jury of all students :-

$\dfrac{39325}{134596}=\dfrac{3575}{12236}$

3 0

2 years ago