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vredina [299]
3 years ago
5

Four times a number is added to 5. The sum is then divided by 6. The result is 7/2. Find the number.

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Hi!

The set up for the question is like this:

\frac{4x + 5}{6} = \frac{7}{2} \\2*(4x + 5) = 7*6\\8x + 10 = 42\\8x = 42 - 10 = 32\\x = 32/8\\x = 4

Hope this helps!

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Use the quadratic formula to solve the<br> quadratic equation. SHOW ALL WORK.<br> 2 −8+41 = 0
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Answer:

Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

Step-by-step explanation:

We need to solve the equation x^2-8x+41=0 using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i

So, Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

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