9514 1404 393
Answer:
dy/dx = y/(2x)
Step-by-step explanation:
The product formula can be used, along with the power rule.
d(uv) = du·v +u·dv
__
d(y^2/x) = d(18)
2y·dy/x -y^2/x^2·dx = 0
2x·dy -y·dx = 0 . . . . . . . . multiply by x^2/y
dy/dx = y/(2x) . . . . . . . . add y·dx, divide by 2x·dx
A quadratic equation has the general form
of: <span>
y=ax² + bx + c
It can be converted to the vertex form in order
to determine the vertex of the parabola. It has the standard form of:
y = a(x+h)² - k
This can be done by completing a square. The steps are as follows:
</span><span>y = 3x2 + 9x – 18
</span>y = 3(x2 <span>+ 3x) – 18
</span>y + 27/4= 3(x2 <span>+ 3x+ 9/4) – 18
</span>y = 3(x2 + 3/2)^2 – 99<span>/4
</span>
Therefore, the first step is to group terms with the variable x and factoring out the coefficient of x^2.
Answer:
From the origin, move 0.5 unit to the left along the x-axis and 1 unit vertically down, and place the point.
Step-by-step explanation:
hope this helps! :}
Answer:
m = variables
+4 = Coefficients
-7 = Coefficients
and 2 and 6 are Constants
Hope this helps!
Step-by-step explanation:
Answer: .........34,650
Step-by-step explanation:
