Question

List the angles in triangle QRS from smallest to largest.

Answer 1

Answer:

angle R

Step-by-step explanation:

To solve this we will use cosine rule

Cosine rule

cos(A) = $\frac{b^{2}+c^{2}-a^{2}}{2bc}$

suppose,

q = 6.25

s = 11.04

r = 13.19

angleQ = $cos^{-1}(\frac{13.19^{2}+11.04^{2}-6.52^{2}}{2(13.19)(11.04)})$

            = 30.58

angleR = $cos^{-1}(\frac{6.52^{2}+11.04^{2}-13.19^{2}}{2(6.52)(11.04)})$

            = 93.82

angleS =  $cos^{-1}(\frac{6.52^{2}+13.19^{2}-11.04^{2}}{2(6.52)(13.19)})$

            = 56.63