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2 years ago

10

Oliver works 5 days a week. He drives 53 kilometres each day and walks a total of 25 kilometres over the week: He uses the follo

wing formula to calculate how far he travels in a working week.
Distance travelled = (53 km + 5 km) x number of days. How far does he travel in total?

1 answer:

nikklg [1K]2 years ago

7 0

I think it’s 36 but I’m not good at math so don’t count me on it

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Simplify. Show your work.

alex41 [277]

1 5/6 is the correct answer.

8 0

3 years ago

ioda

Answer:

$ 338.70

Step-by-step explanation:

https://www.calculatorsoup.com/calculators/financial/loan-calculator-simple.php?pv=15%2C000.00&ratepercent=4&t=48&time_t=month&given_data_last=find_pmt&action=solve

6 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

Points R, S, and T are collinear, and S is between R and T, in addition, RS = 2x-4, ST = 3x+2, and RT = 13. Find the value of RS

Alex17521 [72]

Answer:

RS = 2

Step-by-step explanation:

Points R, S, and T are collinear, and S is between R and T, in addition, RS = 2x-4, ST = 3x+2, and RT = 13. Find the value of RS

Hence:

RS + ST = RT

2x - 4 + 3x + 2 = 13

2x + 3x - 4 + 2 = 13

5x - 2 = 13

5x = 13 + 2

5x = 15

x = 15/5

x = 3

To find the value of RS

RS = 2x-4

RS = 2 × 3 - 4

RS = 6 - 4

RS = 2

5 0

3 years ago

A snail going full speed was taking 1/5 of a minute to move

cluponka [151]

Answer:

84 seconds or 1 min and 24 seconds

Step-by-step explanati

8 0

3 years ago