Answer:
15:20
15/20
15 to 20
there are 3 types of ways and there you go.
Step-by-step explanation:
have a great day ! :)
The standard form of the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle, (x,y) is a point of the circle, and r is the length of the radius of the circle. When the equation of a circle is written, h,k, and r are numbers, while x and y are still variables. (x-2)^2 + (y-k)^2 = 16 is an example of a circle. The problem gives us two of the three things that a circle has, a point (5,9) and the center (-2,3). We need to find the radius in order to write the equation. We substitute -2 for h, 3 for k, 5 for x, and 9 for y to get (5 - (-2))^2 + (9 - 3)^2 = r^2 We simplify: 49 + 36 = r^2, r^2 = 85. We only need to know r^2 because the equation of a circle has r^2. We now have all the information to write the equation of a circle. (x + 2)^2 + (y - 3)^2 = 85.
Answer:
This means that the correct initial value problem for the population p(t) as a function of time is is 
Step-by-step explanation:
The population of a town increases at a rate proportional to its population:
This means that this situation is modeled by the following differential equation:

In which k is the growth rate.
By separation of variables, the solution is given by:

In which P(0) is the initial population.
Initial population of 1000.
This means that the correct initial value problem for the population p(t) as a function of time is is 

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.
We'll take log of each side.
Log of what base tho?
Well, the base of our exponential is e,
so we'll take log base e of each side.

We'll apply one of our log rules next:

This allows us to take the exponent out of the log,

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,



So our equation simplifies to this,

As a final step, divide both sides by 3,

k, hope that helps!