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Andreas93 [3]
1 year ago
7

The product of 1/2 and 2/15 is a/an ________________.

Mathematics
1 answer:
Dvinal [7]1 year ago
8 0

Answer:

irrational

Step-by-step explanation:

Irrational + irrational = irrationL

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Find the median and mode(s)of the data set 53,53.5,57,54,54.5,47,55,54.5​
ella [17]

Answer:

the median is the middle number.

and the mode is the number that occurs most.

so if we put everything in order

53, 53.5, 54, 54.5, 54.5, 55, 57

so the mode would be 54.5 cause it occurs twice

and the median would be somewhere in between 54 and 54.5

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what is the volume of this cone use Pi 3.14 and round your answer to the nearest hundredth radius 14 height 14
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The volume of the cone is 3.14 x 14 x 14
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What numbers add to 33 and muliplies to 75
labwork [276]
<span>33 =1, 3, 11, 33 
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3 years ago
I need help, i do not understand, this is pythagorean theorem
ser-zykov [4K]

Answer:

11.2

Step-by-step explanation:

First draw an imaginary straight line to separate the two shapes.

You will have a side of 10 in the traingle

And a side of 13 - 8 =5

Then

Using pythagoras theorem

Sqrt(10^2+5^2)=11.180

5 0
3 years ago
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.&lt;b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
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