For each of the problems for example #11 tells you to find the measure of angle ABC ABH=46 HBC=120
Therefore you just add the 2 together to get 166
So for #12 its a little diffrent the line is straight so it equals 180 degrees they give you one angle so 180-95= 85
Makes sense?
Step-by-step explanation:
in such a case the easiest approach might be using the point-slope form of a line equation :
y - y1 = m(x - x1)
with m being the slope, and (x1, y1) being a point on the line.
so, in our case that would be
y - 8 = 8(x - 4)
simplified this would be
y - 8 = 8x - 32
y = 8x - 24
FYI - this would be then the slope-intercept form (-24 would be the intercept point on the y-axis).
Answer:

Step-by-step explanation:


Answer:
128
Step-by-step explanation:
-7x+2 = -18(-7)+2=126+2=128