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Novosadov [1.4K]
3 years ago
10

Plz answer quick giving brainliest

Mathematics
2 answers:
dusya [7]3 years ago
7 0
Simplify using FOIL 15x3+18x+10x2+12
Orlov [11]3 years ago
4 0
The answer is (3x+2)(5x^2+6)
Please mark brainelist
You might be interested in
Kurt drew a rectangular maze with the length of 3/4 foot and a width of 5/12 foot.
pochemuha
I hope this helps you



Area =3/4.5/12


Area =5/4.4


Area =5/16
4 0
3 years ago
Simplify the expression. (15 + 8)[23 – (10 + 7)]
wariber [46]
(23)(23-17)
(23)(6)
138
3 0
3 years ago
In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.
Finger [1]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

7 0
2 years ago
Read 2 more answers
Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

which means the series converges everywhere (independently of x), and so the radius of convergence is infinite.
3 0
3 years ago
Simplify the expression to a polynomial in standard form:<br> (3x – 10)(x2+ 2x - 1 )
KonstantinChe [14]

Answer:

3 x ^3  −  4 x ^2  −  23 x  +  10

Step-by-step explanation:

hope this helps!

3 0
3 years ago
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