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3 years ago

the square root of a number is subtracted from the sum of the number and 12. the result is 42. what is the original number?

Mathematics

1 answer:

Akimi4 [234]3 years ago

3 0

x +12 -sqrt(x) = 42

-sqrt(x) = -x+30

-sqrt(x)^2 = (-x+30)^2

x^2 - 61x + 900 = 0

(x-36) (x-25) = 0

x = 36

36+12 = 48 - sqrt(36) = 48-6 = 42

X = 36

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