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3 years ago

What is the value of x angle in a circle with center O?

Mathematics

1 answer:

AysviL [449]3 years ago

8 0

Answer:

Correct me if i am wrong but i believe it is 126

Step-by-step explanation:

Angle BOC = 252 (angles around a point = 360 so 360-108 =252)

x=126 (The ange at the centre of a circle is twice the size the angle at the circumference. 252 is at the centre and x is at the circumference so 252/2 = 126)

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Find the domain and range of f(x) = -|x|

DochEvi [55]

Answers:
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Domain: {x| x = <span>ℝ} .
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Range: {y| y <span>≤ 0 } .
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3 years ago

The triangle P(1.-4), U(5,0) and N(2, 1) is reflected over the y-axis. What are the coordinates of the new points?

vichka [17]

Answer:

Step-by-step explanation:

Reflection of x axis

1) the new points have the same x coordinates

2) the new point have the opposite y coordinates

P (1;4) ; U (5;0) ; N(2;-1)

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3 years ago

Let P(t) be a population at time t. A simple population model supposes the rate of growth of the population is proportional to t

jeka94

Answer:

$(a) \dfrac{dP}{dt} =k P(t)\\(b)P(t)=Ce^{kt}$

(ii) $P(1000)\approx 26.88 \times 10^{44}\\$

Step-by-step explanation:

(a)The rate of growth of the population is proportional to the population, this is written as:

$\dfrac{dP}{dt} \propto P(t)\\$Introducing our proportionality constant, k\\ \dfrac{dP}{dt} =k P(t)$

(b)

$\dfrac{dP(t)}{P(t)} =k dt\\$Take the integral of both sides\\\int \dfrac{dP(t)}{P(t)} =\int k dt\\\ln P(t)=kt+C, $C a constant of integration\\Take the exponential of both sides\\e^{\ln P(t)}=e^{kt+C}\\P(t)=e^{kt}\cdot e^C $, (Since e^C$ is a constant, we then have:)\\P(t)=Ce^{kt}$

(c)

Suppose the net birthrate of the population is .1, and the initial population is 100.

k=0.1

P(0)=100

Substitution into P(t) gives:

$100=Ce^{kX0}$

C=100

Therefore:

$P(t)=100e^{0.1t}$

(i)When t=10

$P(10)=100e^{0.1 \times 10}\\=271.8\\\approx 272$

(ii)When t=1000

$P(1000)=100e^{0.1 \times 1000}\\=26.88 \times 10^{44}\\$

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4 years ago

Find the values of A and B<br> PLEASE HELP GIVING BRAINLIEST

erastovalidia [21]

Factoring the roots, the values of A and B are given as follows:

A = 3z.

B = 2.

<h3>What are the values of A and B?</h3>

The expression is:

$\sqrt{\frac{45\alpha z^3}{40y}} = \frac{A\sqrt{\alpha z}}{B\sqrt{2y}}$

We have that:

$\frac{45}{40} = \frac{9}{8}$

Hence:

$\sqrt{\frac{45\alpha z^3}{40y}} = \sqrt{\frac{9\alpha z^3}{8}} = \sqrt{\frac{9\alpha z^2 \times z}{4 \times 2}} = \frac{A\sqrt{\alpha z}}{B\sqrt{2y}}$

Hence, comparing the last two equalities:

A = 3z.

B = 2.

More can be learned about the factoring of roots at brainly.com/question/24380382

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2 years ago

The graph of a proportional relationship passes through the points (0.5, 6) and (x,24). Find x.

laila [671]

Answer:

..................

Step-by-step explanation:

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3 years ago