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tankabanditka [31]
2 years ago
10

K, L, and M are points on the circle. KS is a tangent to the circle at K. KM is a diameter and triangle KLM is isosceles. Find t

he value of z.

Mathematics
1 answer:
Paraphin [41]2 years ago
6 0

Using the circle theorems, the value of z is 45

<h3>Circle Geometry </h3>

From the question, we are to determine the value of z

From the given information,

KM is a diameter

∴ ∠KLM = 90° (<em>Angle in a semicircle</em>)

Also, ΔKLM is isosceles

∴ ∠KML = ∠MKL (<em>Base angles of an isosceles triangle</em>)

Then,

∠KML + ∠MKL + ∠KLM = 180° (<em>Sum of angles in a triangle</em>)

2× ∠KML + 90° = 180°

2× ∠KML = 180° - 90°

2× ∠KML = 90°

∠KML = 90°/2

∠KML = 45°

Now, we can observe that

z° = ∠KML (<em>Angles in alternate segment</em>)

But,

∠KML = 45°

∴ z = 45

Hence, the value of z is 45

Learn more on Circle Geometry here: brainly.com/question/17074363

#SPJ1

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Answer:

Step-by-step explanation:

From the given information:

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interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

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To find their regular monthly payment, we have:

PV = P \begin {bmatrix}  \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}}    \end {bmatrix}

128000 = P \begin {bmatrix}  \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}}    \end {bmatrix}

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P = $921.433

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To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

PV= 921.433 \begin {bmatrix}  \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}}    \end {bmatrix}

PV = $121718.2714

C) In order to estimate how many payments of $1400  it will take to pay off the loan, we have:

121718.2714 =  \begin {bmatrix}  \dfrac{1300  (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}}    \end {bmatrix}

121718.2714 = 200000  \begin {bmatrix}  (1 - \dfrac{12.078}{12}))^{-nt}   \end {bmatrix}

\dfrac{121718.2714}{200000 } =  \begin {bmatrix}  (1 - \dfrac{12.078}{12}))^{-nt}   \end {bmatrix}

0.60859 =  \begin {bmatrix}  (1 - \dfrac{12}{12.078}))^{nt}   \end {bmatrix}

0.60859 = (0.006458)^{nt}

nt = \dfrac{0.60859}{0.006458}

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88  - 177795.38

The amount of interest saved = $153920.5

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Help with this algebra question
Degger [83]
We have:
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 We have then:
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y = (- 3/4) x + 3
 
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