Given:
15. 
17. 
19. 
To find:
The values of the given logarithms by using the properties of logarithms.
Solution:
15. We have,

Using property of logarithms, we get
![[\because \log_aa=1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%3D1%5D)
Therefore, the value of
is 1.
17. We have,

Using properties of logarithms, we get
![[\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D-%5Clog_a%5Cdfrac%7Bn%7D%7Bm%7D%5D)
![[\because \log_aa=1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%3D1%5D)
Therefore, the value of
is -1.
19. We have,

Using property of logarithms, we get
![[\because a^{\log_ax}=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E%7B%5Clog_ax%7D%3Dx%5D)
Therefore, the value of
is 100.
5 horses with a combined weight of 6,240 pounds
horse trailer has a limit of 8,000 pounds of horse and tacks.
Find the weight of tack, t, for each horse that Cari can allow.
5t + 6,240 < 8,000
5t + 6,240 < 8,000
- 6,240 -6,240
5t < 1,760
<span>÷5 ÷5 </span>
t < 352
Each horse can carry a tack that weighs no more than 352 pounds.
Any tack that weighs beyond <span>352 </span>pounds is will exceed the maximum carrying capacity of the horse trailer.
Answer:
610 cm
Step-by-step explanation:
78.9 x 100 = 7890 cm 85 x 100 = 8,500 cm
8,500 - 7890 = 610 cm