All categories

3 years ago

Where is the opposite of 8 located on a number line?

Mathematics

2 answers:

Rus_ich [418]3 years ago

4 0

A) to the left of 0

zlopas [31]3 years ago

3 0

A, to the left of 0, because -8 is the opposite of 8, and negatives are on the left side.

You might be interested in

6/100 equals what as a decimal?

Dahasolnce [82]

Answer:

0.06

Step-by-step explanation:

hope this helps

6 divide by 100= 0.06

3 0

3 years ago

Read 2 more answers

HELPPP PLEASE!!! IM BEING TIMED!!!

Elena-2011 [213]

Answer:

y=2x+4

Step-by-step explanation:

8=2(6)+b

8=12+b

4=b

5 0

3 years ago

PLEASE HELP ME............THANKS

Stolb23 [73]

Answer:

i think it's c, I could be wrong djxndnxmmx

6 0

3 years ago

Read 2 more answers

HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid

Harlamova29_29 [7]

Answer: Missing parts are,

In first blank, $AD\cong DC$ ,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

$\angle BDA\cong \angle BDC$ ( right angles )

$BD\cong BD$ ( reflexive)

Thus, By SAS ( side angle side )postulate,

$\triangle ADB\cong \triangle CDB$

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

$AB\cong CB$

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.

7 0

3 years ago

Read 2 more answers

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago