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dybincka [34]
2 years ago
12

Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

if β > α.
sin(x/2+20)=cos(2x-25/2)


A) 25°
B) 33°
C) 36.5°
D) 53.5°

HINT: Sine and cosine of complementary angles are related
Mathematics
1 answer:
igomit [66]2 years ago
5 0

Answer:

D) 53.5°

Step-by-step explanation:

Sine and cosine of complementary angles are equal:

sin θ = cos(90 − θ)

sin(x/2 + 20) = cos(2x − 25/2)

cos(90 − (x/2 + 20)) = cos(2x − 25/2)

90 − (x/2 + 20) = 2x − 25/2

90 − x/2 − 20 = 2x − 25/2

165/2 = 5x/2

5x = 165

x = 33

x/2 + 20 = 36.5

2x − 25/2 = 53.5

Since β > α, β = 53.5°.

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Triangle ABC is inscribed in the circle, mA=50, and AB=BC. Find arch AC.
Karolina [17]

The answer is C) 160.

We know this because if mA = 50, we know that mC must also be 50. This is due to the fact that AB = BC. This leaves us with mB as 80 since the angles of a triangle always have to equal 180.

Now knowing this, it is easy to find the arc lengths in degrees. When you have a transcribed triangle, all we are going to do here is double the angle of the triangle to get the arc measure.

mB = 80

80*2 = 160

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3 years ago
Ben has a rectangular area 9 meter long and 5 meters wide he wants a fence that will go around it as well as grass sod to cover
fgiga [73]

I think the answer is A.

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Alma was given some money as a gift and deposited it into a savings account. She makes a withdrawal of the same amount at the en
Kryger [21]

Answer:

input= starting amount

output= withdrawals

(5,442) and (13,226)

Step-by-step explanation:

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Hope this helps!

5 0
2 years ago
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3 0
2 years ago
Use the t-distribution and the sample results to complete the test of the hypotheses. Use a significance level. Assume the resul
Ksenya-84 [330]

Answer:

Test statistic = 1.3471

P-value = 0.1993

Accept the null hypothesis.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 4

Sample mean, \bar{x} = 4.8

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 2.3

First, we design the null and the alternate hypothesis

H_{0}: \mu = 4\\H_A: \mu \neq 4

We use two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{4.8 - 4}{\frac{2.3}{\sqrt{15}} } = 1.3471

Now, we calculate the p-value.

P-value = 0.1993

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept it.

3 0
3 years ago
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