If m/CHF = 106°, then what is m/FHD?
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Given:
The length of the marathon is L= 46,145 yards.
The length covered by terrence is d = 23,561 yrads.
The objective is to find the remaining distance need to cover by terrence.
To calculate the remaining distance, we will use the relation,
On plugging the values in the above relation, we get,
Hence, Terrence needs to run about 23000 yards.