Answer:
1) m ∠B = 132°
2) m ∠B = 113°
Step-by-step explanation:
1. In triangle ABC, m ∠A=36, and m ∠C=12. Calculate m ∠B.
We are given measure of 2 angles and we need to find the third angle.
We know that, sum of angles of triangle = 180°
We can write as:
∠A + ∠B + ∠C = 180°
Now put m ∠A=36 and m ∠C=12, to find m ∠B
So, we get m ∠B = 132°
2. In triangle ABC, m ∠A=40, and m ∠C=27. Calculate m ∠B.
We are given measure of 2 angles and we need to find the third angle.
We know that, sum of angles of triangle = 180°
We can write as:
∠A + ∠B + ∠C = 180°
Now put m ∠A=40 and m ∠C=27, to find m ∠B
So, we get m ∠B = 113°
The answer is 3x^2 + 6x + 4 (the second one)
Let's start by removing the parenthesis to get 6x + 7 + x^2 + 2x^2 - 3
Then, let's combine like terms (terms with the same variable and exponent) to get 3x^2 + 6x + 4
This is an answer in the multiple choice, so the answer is 3x^2 + 6x + 4 (the second one)
This is the concept of geometry, the function given by f(x)=cos^x
can be written as cos y=x
The domain if the function is [-1,1] and the range is given by [0,π] where π=180°
Two supplementary angles when addd together equal 180.
let one angle = x
The second angle is 5 times that so would be 5x
x + 5x = 180
Simplify:
6x = 180
Divide both sides by 6:
X = 30
One angle is 30, the second angle would be 150
The answer is 150
Answer:
They are both 117*
Step-by-step explanation:
