1) y-intercept => x = 0, => y = f(0) = 0 - 0 + 0 - 36 = -36
2) x-intercept => y = 0 => factor the function (start by dividing by x -2)
f(x) = (x-2)(x-3)(x-6) =0 => x =2, x = 3, x = 6 (these are the x-intercepts)
3) critical points:
between x = 2 and x = 3, there is a local maximum
between x =3 and x = 6 there is a local minimum
3) Shape.
The function comes growing from - infinity.
In the third quadrant the function is negative (it does not pass throuhg the second quadrant)
It enters to the fourth quadrant intercepting the y-axis at y = -36. It continues growing and intercepts the x-axis at x = 2.
It continues increasing until a maximum local positive value, starts to decrease, intercepts the x-axis at x = 3, continues decreasing, becomes negative, gets a local minimum in the fourth quadrant, starts to increase, intercepts the x-axis at x = 6, becomes positive, and continues growing.
Since both 2 and 5 are prime numbers, there are no multiples for the fraction 2/5.
Answer:
90
Step-by-step explanation:
10! / (10 - 2)!
=10!/8!
=10 * 9 * 8! /8!
=90 * 8!/8!
90
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Given :


Now, Substituing the value of y in equation (ii) :








Now, substituting the value of x in equation (i) :




Find the base and height of each side, subtract the triangle from the trapezoid then find the area of the parrellogram and add the subracted one and the obtuse square