Answer:
611.064 kJ
Explanation:
Given :
m = 200 mL = 200 g
Specific heat of ice = 2.06 J/g°C
Q = mcΔt
Δt = 0 - (-22) = 22
Q1 = 200 * 2.06 * 22 = 9064 J
Q2 = Melt 0 °C solid ice into 0 °C liquid water:
Q2 = m · ΔHf ; ΔHf = heat of fusion of water = 334j/g
Q2 = 200 * 334 = 66800 J
Q3 : Heat to convert from 0°C to 100°C
Q3 = mcΔt ; c = 4.19 J/g°C ; Δt = (100 - 0) = 100
Q3 = 200 * 4.19 * 100 = 83800 J
Q4: heat required to boil water to steam
Q = m · ΔHv
Hv = heat of vaporization of water = 2257 J/g
Q4 = 200 * 2257 = 451400 J
Total Q = Q1 + Q2 + Q3 + Q4
Q = 9064 + 66800 + 83800 + 451400
Q = 611,064 Joules
Q = 611.064 kJ
Explanation:
Speed = 10 and miles = 5
(a) Speed + 12 – miles * 2
10 + 12 - 5 × 2
= 12
(b) speed + miles × 3
10 + 5 × 3
= 25
(c) (speed + miles) × 3
(10 + 5) × 3
= 45
(d) speed + speed × miles + miles
10 + 10 × 5 + 5
= 65
(e) (10 – speed) + miles / miles
(10 - 10) + 5/5
= 1
Therefore, this is the required solution.
Answer:
a)
b)
Explanation:
Apparent frequency of the siren is given as
as we know that the wavelength will remain the same as it is having originally
sowe know
a) Now when wind is blowing from source to official
so we have
so we have
b) Now when wind is from official to source
so we have
so we have
Answer:
D. 2^(3/2)
Explanation:
Given that
T² = A³
Let the mean distance between the sun and planet Y be x
Therefore,
T(Y)² = x³
T(Y) = x^(3/2)
Let the mean distance between the sun and planet X be x/2
Therefore,
T(Y)² = (x/2)³
T(Y) = (x/2)^(3/2)
The factor of increase from planet X to planet Y is:
T(Y) / T(X) = x^(3/2) / (x/2)^(3/2)
T(Y) / T(X) = (2)^(3/2)
