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makvit [3.9K]
3 years ago
5

Determine the magnitude of the minimum acceleration at which the thief can descend using the rope. Express your answer to two si

gnificant figures and include the appropriate units.
Physics
1 answer:
iVinArrow [24]3 years ago
8 0

Answer: hello your question is incomplete below is the missing part

A 69-kg petty thief wants to escape from a third-story jail window. Unfortunately, a makeshift rope made of sheets tied together can support a mass of only 58 kg.

answer:

To 2 significant Figures = 1.6 m/s^2

Explanation:

<u>Calculate the magnitude of minimum acceleration at which the thief can descend </u>

we apply the relation below

Mg - T = Ma  --- ( 1 )

M = 69kg

g = 9.81

T = 58 * 9.81

a = ? ( magnitude of minimum acceleration)

From equation 1

a = [ ( 69 * 9.81 ) - ( 58 * 9.81 ) ] / 69

  = 1.5639 m/s^2

To 2 significant Figures = 1.6 m/s^2

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A thin uniform cylindrical turntable of radius 2.2 m and mass 35 kg rotates in a horizontal plane with an initial angular speed
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Explanation:

The given data is as follows.

    M = 35 kg,    radius (r) = 2.2 m,

     m = 17 kg,     = 11 rad/s

We assume that will be the final angular speed.

Now, according to the conservation of angular momentum.

         L_{1} = L_{2}

or,    I_{1} \times \omega_{1} = I_{2} \times \omega_{2}

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  I_{1} \times \omega_{1} = I_{2} \times \omega_{2}

   

or,  

      = \frac{(0.5 \times 35 \times (2.2)^{2}) \times 11}{(0.5 \times 35 \times (2.2)^{2} + 17 \times (1.5)^{2})}

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A snowball is rolling down a hill at 4.5 m/s and accumulating snow as it goes. Its diameter begins at 0.50 m and ends at the bot
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To find the change in centripetal acceleration, you should first look for the centripetal acceleration at the top of the hill and at the bottom of the hill.

The formula for centripetal acceleration is:
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where:
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r= radium, m

assuming the velocity does not change:

at the top of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 0.25 m
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at the bottom of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 1.25 m
                                      = 16.2 m/s^2

to find the change in centripetal acceleration, take the difference of the two.
change in centripetal acceleration = centripetal acceleration at the top of the hill - centripetal acceleration at the bottom of the hill

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