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enyata [817]
2 years ago
15

What volume (in mL) of 0.250 M HCI would be

Chemistry
1 answer:
Nitella [24]2 years ago
4 0

Answer: 1820 mL (to 3 sf)

Explanation:

The atomic mass of aluminum is 26.9815385 g/mol, so 4.10 g of aluminum is equal to 4.10/26.9815385 = 0.15195575300497 moles of Al.

From the coefficients of the equation, we know that for every 2 moles of aluminum consumed, 6 moles of HCl are consumed.

So, this means we need 0.15195575300497(6/2) = 0.45586725901491 moles of HCl.

Substituting into the molarity formula,

  • 0.250 = 0.45586725901491/(liters of HCl)
  • liters of HCl = 0.45586725901491/0.250
  • liters of HCl = 1.8234690360596 L = 1820 mL (to 3 sf)
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Density = Mass / Volume
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M = 22.57 g/cm³ * 10 cm³
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Explanation

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Which statement applies to electronegativity?
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Mg + 2HCl → MgCl2 + H2
deff fn [24]

Answer:

Explanation:

This is a limiting reactant problem.

Mg(s)

+

2HCl(aq)

→

MgCl

2

(

aq

)

+ H

2

(

g

)

Determine Moles of Magnesium

Divide the given mass of magnesium by its molar mass (atomic weight on periodic table in g/mol).

4.86

g Mg

×

1

mol Mg

24.3050

g Mg

=

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Determine Moles of 2M Hydrochloric Acid

Convert

100 cm

3

to

100 mL

and then to

0.1 L

.

1 dm

3

=

1 L

Convert

2.00 mol/dm

3

to

2.00 mol/L

Multiply

0.1

L

times

2.00 mol/L

.

100

cm

3

×

1

mL

1

cm

3

×

1

L

1000

mL

=

0.1 L HCl

2.00 mol/dm

3

=

2.00 mol/L

0.1

L

×

2.00

mol

1

L

=

0.200 mol HCl

Multiply the moles of each reactant times the appropriate mole ratio from the balanced equation. Then multiply times the molar mass of hydrogen gas,

2.01588 g/mol

0.200

mol Mg

×

1

mol H

2

1

mol Mg

×

2.01588

g H

2

1

mol H

2

=

0.403 g H

2

0.200

mol HCl

×

1

mol H

2

2

mol HCl

×

2.01588

g H

2

1

mol H

2

=

0.202 g H

2

The limiting reactant is

HCl

, which will produce

0.202 g H

2

under the stated conditions.

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