All categories

2 years ago

What volume (in mL) of 0.250 M HCI would be

Chemistry

1 answer:

Nitella [24]2 years ago

4 0

Answer: 1820 mL (to 3 sf)

Explanation:

The atomic mass of aluminum is 26.9815385 g/mol, so 4.10 g of aluminum is equal to 4.10/26.9815385 = 0.15195575300497 moles of Al.

From the coefficients of the equation, we know that for every 2 moles of aluminum consumed, 6 moles of HCl are consumed.

So, this means we need 0.15195575300497(6/2) = 0.45586725901491 moles of HCl.

Substituting into the molarity formula,

0.250 = 0.45586725901491/(liters of HCl)
liters of HCl = 0.45586725901491/0.250
liters of HCl = 1.8234690360596 L = 1820 mL (to 3 sf)

You might be interested in

I'm not 100% sure of the answer. Explanations are highly appreciated.

PolarNik [594]

Answer:

The correct answer is

$\Delta H=2(1072)+498 -4(799)$

Explanation:

Enthalpy of reaction :

It is the amount of energy released/absorbed when one mole of the substance is formed from the reactant at a constant pressure.

The enthalpy of a reaction can be calculated using :

$\Delta H=\Delta H_{reactants}-\Delta H_{products}$

$2CO+O_{2}\rightarrow 2CO_{2}$

$\Delta H_{reactants}=2(C\equiv O)+O=O$

$\Delta H_{reactants}=2(1072)+498$

$H_{products}=2(2\times C=O)$

$H_{products}=4\times 799$

$\Delta H=\Delta H_{reactants}-\Delta H_{products}$

$\Delta H=2(1072)+498 -4(799)$

$units = \frac{kJ}{mole}$

Please note that :

The carbon monoxide , CO should be taken as C triple bond O. Not C=O .

So , the bond energy =1072 is used

$\Delta H=2(1072)+498 -4(799)$

8 0

3 years ago

If have a volume of 18 L of a gas at a temperature of 272 K and a pressure of 90 atm, what will be the pressure of the gas if ra

Solnce55 [7]

Answer:

P₂ ≅ 100 atm (1 sig. fig. based on the given value of P₁ = 90 atm)

Explanation:

Given:

P₁ = 90 atm P₂ = ?

V₁ = 18 Liters(L) L₂ = 12 Liters(L)

=> decrease volume => increase pressure

=> volume ratio that will increase 90 atm is (18L/12L)

T₁ = 272 Kelvin(K) T₂ = 274 Kelvin(K)

=> increase temperature => increase pressure

=> temperature ratio that will increase 90 atm is (274K/272K)

n₁ = moles = constant n₂ = n₁ = constant

P₂ = 90 atm x (18L/12L) x (274K/272K) = 135.9926471 atm (calculator)

By rule of sig. figs., the final answer should be rounded to an accuracy equal to the 'measured' data value having the least number of sig. figs. This means P₂ ≅ 100 atm based on the given value of P₁ = 90 atm.

3 0

2 years ago

Convert 76.78 g of CO2 to a volume.

Jlenok [28]

Brainest please thank you

5 0

3 years ago

Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, how many

prisoha [69]

337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles