In order to <span>decrease the pressure of a gas inside a closed cubical container, you need to decrease the temperature of the container. The volume of the system is rigid so it means volume is constant. By the ideal gas law, temperature and pressure are directly related. Increasing the temperature, increases the pressure and the opposite to happens.</span>
..........The answer is B
4FeS2 + 11O2-> 2Fe2O3 + 8SO2
Not sure.... I think this is it
He was not all the way up the ladder he was only on the first couple steps