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bagirrra123 [75]

3 years ago

15

iron cross is a skiing trick in which the tips of the skis are crossed while the skier is airborne. Find the value of x in the i

ron cross shown

1 answer:

erastova [34]3 years ago

8 0

Answer:

no quema cuh

Step-by-step explanation:

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Write <br> 9<br> 5<br> as a mixed number.

Advocard [28]

<span>Well, think of it this way? How many times does 5 go into 9?

5 * 1 = 5
5 * 2 = 10

So 5 goes into 9 one time. Then you have to subtract that 5 from 9 to be left with your fraction value.

1 and 4/5 is your mixed number.</span>

5 0

3 years ago

Read 2 more answers

Passing through (2, - 2) and perpendicular to the line whose equation is y= 5x+2

jonny [76]

Step-by-step explanation:

Hey there!!!

Here,

Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.

The equation of a straight line passing through point is,

$(y - y1) = m1(x - x1)$

Now, put all values.

$(y + 2) = m1(x - 2)$

It is the 1st equation.

Another equation is;

y = 5x +2........(2nd equation).

Now, Comparing it with y = mx + c, we get;

m2=5

As per the condition of perpendicular lines,

m1×m2= -1

m1 × 5 = -1

Therefore, m2= -1/5.

Keeping the value of m1 in 1st equation.

$(y + 2) = \frac{ - 1}{5} (x - 2)$

Simplify them.

$5(y + 2) = - x + 2$

$5y + 10 = - x + 2$

$x + 5y + 8 = 0$

Therefore the required equation is x+5y+8= 0.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0

3 years ago

HELP PLEASE!!! WILL GIVE BRAINLIEST

Nadusha1986 [10]

The equation looks like this $\frac{ x^{2} }{16} + \frac{ y^{2} }{25} =1$ . In an ellipse, a is always the bigger value, so a^2 = 25. This bigger value also tells us which axis is the major one. Sine the bigger value a is under the y^2 of the equation, the major axis is the y-axis. This is a vertical ellipse. The center is always found within a set of parenthesis that exist with the x^2 and the y^2. Since there are no parenthesis with either, there is no side to side movement, nor is there any up or down movement. So the center doesn't move from the origin (0, 0). The vertex is also along the major axis, and if a^2 is 25, then a = 5, so the vertices go up 5 from the center and down 5 from the center. Vertices are (0, 5) and (0, -5). The foci follow the formula $c^{2}= a^{2}- b^{2}$ . c is the distance that the foci are from the center. $c^{2}=25-16$ and c = 3. The foci also lie on the major axis, so the coordinates for the foci are (0, 3) and (0, -3). There you go!

8 0

3 years ago

Please give me the the answer of the question in the link that's 50 points

svetoff [14.1K]

Answer:

B. y=−5x+1152

Step-by-step explanation:

7 0

3 years ago

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Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

so

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$

therefore

the answer is

$581.25$

6 0

3 years ago

Read 2 more answers